美文网首页
415. Add Strings

415. Add Strings

作者: hyhchaos | 来源:发表于2016-12-01 12:57 被阅读15次

    Java

    public class Solution {
        public String addStrings(String num1, String num2) {
            int tmp=0;
            int k=0;
            int length1=num1.length();
            int length2=num2.length();
            int min=length1>length2? length2:length1;
            int max=length1>length2? length1:length2;
            String use;
            if(length1>length2) 
            use=num1;
            else 
            use=num2;
            String string="";
            int i;
            for(i=0;i<max;)
            {
                int bitAdd;
                if(i<min)
                bitAdd=((int)num1.charAt(length1-1-i)-(int)('0')+(int)num2.charAt(length2-1-i)-(int)('0')+tmp);
                else
                bitAdd=((int)use.charAt(max-1-i)-(int)('0')+tmp);
                
                k=bitAdd%10;
                tmp=bitAdd/10;
                System.out.println(bitAdd);
                string=k+""+string;
                i++;
            }
            if(tmp!=0) string=tmp+""+string;
            return string;
        }
    }
    

    Javascript

    /**
     * @param {string} num1
     * @param {string} num2
     * @return {string}
     */
    var addStrings = function(num1, num2) {
            var tmp=0;
            var k=0;
            var length1=num1.length;
            var length2=num2.length;
            var min=length1>length2? length2:length1;
            var max=length1>length2? length1:length2;
            var use;
            if(length1>length2) 
            use=num1;
            else 
            use=num2;
            var string="";
            var i;
            for(i=0;i<max;)
            {
                var bitAdd;
                if(i<min)
                bitAdd=(parseInt(num1[length1-1-i])+parseInt(num2[length2-1-i])+tmp);
                else
                bitAdd=(parseInt(use[max-1-i])+tmp);
                
                k=bitAdd%10;
                tmp=(bitAdd-k)/10;
                string=k+string;
                i++;
            }
            if(tmp!==0) string=tmp+string;
            return string;
    };
    

    注意Javascript做除法不会取整

    优解,思路差不多,但是他这个写法很简练

    public class Solution {
        public String addStrings(String num1, String num2) {
            StringBuilder sb = new StringBuilder();
            int carry = 0;
            for(int i = num1.length() - 1, j = num2.length() - 1; i >= 0 || j >= 0 || carry == 1; i--, j--){
                int x = i < 0 ? 0 : num1.charAt(i) - '0';
                int y = j < 0 ? 0 : num2.charAt(j) - '0';
                sb.append((x + y + carry) % 10);
                carry = (x + y + carry) / 10;
            }
            return sb.reverse().toString();
        }
    }
    

    相关文章

      网友评论

          本文标题:415. Add Strings

          本文链接:https://www.haomeiwen.com/subject/srsxmttx.html