Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
Example:
Input: n = 4, k = 2
Output:
[
[2,4],
[3,4],
[2,3],
[1,2],
[1,3],
[1,4],
]
解释下题目:
说白了就是加了点条件的全排列罢了。
1. 方法1
实际耗时:51ms
public static List<List<Integer>> combine(int n, int k) {
List<List<Integer>> combs = new ArrayList<>();
combine(combs, new ArrayList<Integer>(), 1, n, k);
return combs;
}
public static void combine(List<List<Integer>> combs, List<Integer> comb, int start, int n, int k) {
if (k == 0) {
combs.add(new ArrayList<Integer>(comb));
return;
}
for (int i = start; i <= n; i++) {
comb.add(i);
combine(combs, comb, i + 1, n, k - 1);
comb.remove(comb.size() - 1);
}
}
思路很简单。就是全排列的思路。深度优先的算法
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