最近研究 Okhttp3, 把项目 down 下来后,发现不能编译,真实尴尬。平时使用的都是 gradle, 但是该项目使用 maven,导入 idea 后,摸索两下,用界面的命令行搞起。
image.png项目中有好多 model, 本次主要看看 Okhttp3 的 get/post 请求。其实我们自己很容易就能写出来,不过还是看看 官方 demo 的写法吧。
get 请求
public class GetExample {
OkHttpClient client = new OkHttpClient();
String run(String url) throws IOException {
Request request = new Request.Builder()
.url(url)
.build();
try (Response response = client.newCall(request).execute()) {
return response.body().string();
}
}
public static void main(String[] args) throws IOException {
GetExample example = new GetExample();
String response = example.run("https://raw.github.com/square/okhttp/master/README.md");
System.out.println(response);
}
}
这个里面需要提到的是 try(需要一次捕获的代码){正常后处理的代码} 这是 java 7.0 以上的 try catch 结构,操作方便。
post 请求
public class PostExample {
public static final MediaType JSON
= MediaType.parse("application/json; charset=utf-8");
OkHttpClient client = new OkHttpClient();
String post(String url, String json) throws IOException {
RequestBody body = RequestBody.create(JSON, json);
Request request = new Request.Builder()
.url(url)
.post(body)
.build();
try (Response response = client.newCall(request).execute()) {
return response.body().string();
}
}
String bowlingJson(String player1, String player2) {
return "{'winCondition':'HIGH_SCORE',"
+ "'name':'Bowling',"
+ "'round':4,"
+ "'lastSaved':1367702411696,"
+ "'dateStarted':1367702378785,"
+ "'players':["
+ "{'name':'" + player1 + "','history':[10,8,6,7,8],'color':-13388315,'total':39},"
+ "{'name':'" + player2 + "','history':[6,10,5,10,10],'color':-48060,'total':41}"
+ "]}";
}
public static void main(String[] args) throws IOException {
PostExample example = new PostExample();
String json = example.bowlingJson("Jesse", "Jake");
String response = example.post("http://www.roundsapp.com/post", json);
System.out.println(response);
}
}
重点在这里『RequestBody.create(JSON, json)』, 构建 post 的 body 的时候,直接传入 mediaType 和 json 内容即可构建成功。
下面还有好多,可以直接在 github 上查看:
image.png异步 get 请求,猜猜结果是什么?
public final class AsynchronousGet {
private final OkHttpClient client = new OkHttpClient();
public void run() throws Exception {
Request request = new Request.Builder()
.url("http://publicobject.com/helloworld.txt")
.build();
client.newCall(request).enqueue(new Callback() {
@Override public void onFailure(Call call, IOException e) {
e.printStackTrace();
}
@Override public void onResponse(Call call, Response response) throws IOException {
try (ResponseBody responseBody = response.body()) {
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
Headers responseHeaders = response.headers();
for (int i = 0, size = responseHeaders.size(); i < size; i++) {
System.out.println(responseHeaders.name(i) + ": " + responseHeaders.value(i));
}
System.out.println(responseBody.string());
}
}
});
System.out.println(" 异步了么?");
}
public static void main(String... args) throws Exception {
new AsynchronousGet().run();
}
}
结果亮起来了:
image.png需要用户登录后才能访问接口
我们 尝试直接访问 http://publicobject.com/secrets/hellosecret.txt
, 会强制我们登录,否则就没有返回值。
登录名: jesse
登陆密码: password1
会看到 android 的密钥哈
public final class Authenticate {
private final OkHttpClient client;
public Authenticate() {
client = new OkHttpClient.Builder()
.authenticator(new Authenticator() {
@Override public Request authenticate(Route route, Response response) throws IOException {
if (response.request().header("Authorization") != null) {
return null; // Give up, we've already attempted to authenticate.
}
System.out.println("Authenticating for response: " + response);
System.out.println("Challenges: " + response.challenges());
String credential = Credentials.basic("jesse", "password1");
return response.request().newBuilder()
.header("Authorization", credential)
.build();
}
})
.build();
}
public void run() throws Exception {
Request request = new Request.Builder()
.url("http://publicobject.com/secrets/hellosecret.txt")
.build();
try (Response response = client.newCall(request).execute()) {
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
System.out.println(response.body().string());
}
}
public static void main(String... args) throws Exception {
new Authenticate().run();
}
}
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