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通过两个经纬度算出方位

通过两个经纬度算出方位

作者: KouKuma | 来源:发表于2016-11-05 17:31 被阅读94次

    pragma mark - 得到角度

    - (double)getAngleLat1:(double)lat1 withLng1:(double)lng1 withLat2:(double)lat2 withLng2:(double)lng2
    {
        double x1 = lng1;
        double y1 = lat1;
        double x2 = lng2;
        double y2 = lat2;
        double pi = M_PI;
        double w1 = y1 / 180 * pi;
        double j1 = x1 / 180 * pi;
        double w2 = y2 / 180 * pi;
        double j2 = x2 / 180 * pi;
        double ret;
        if (j1 == j2) {
            if (w1 > w2)
                return 270; // 北半球的情况,南半球忽略
            else if (w1 < w2)
                return 90;
            else
                return -1;// 位置完全相同
        }
        ret = 4* pow(sin((w1 - w2) / 2), 2)- pow(
                                                                sin((j1 - j2) / 2) * (cos(w1) - cos(w2)),2);
        ret = sqrt(ret);
        double temp = (sin(fabs(j1 - j2) / 2) * (cos(w1) + cos(w2)));
        ret = ret / temp;
        ret = atan(ret) / pi * 180;
        if (j1 > j2){ // 1为参考点坐标
            if (w1 > w2)
                ret += 180;
            else
                ret = 180 - ret;
        } else if (w1 > w2)
            ret = 360 - ret;
        return ret;
    }
    #pragma mark - 得到方向
    - (NSString *)getDirection:(double)jiaodu
    {
        if ((jiaodu <= 10) || (jiaodu > 350))
            return @"东";
        if ((jiaodu > 10) && (jiaodu <= 80))
            return @"东北";
        if ((jiaodu > 80) && (jiaodu <= 100))
            return @"北";
        if ((jiaodu > 100) && (jiaodu <= 170))
            return @"西北";
        if ((jiaodu > 170) && (jiaodu <= 190))
            return @"西";
        if ((jiaodu > 190) && (jiaodu <= 260))
            return @"西南";
        if ((jiaodu > 260) && (jiaodu <= 280))
            return @"南";
        if ((jiaodu > 280) && (jiaodu <= 350))
            return @"东南";
        return @"";
    }

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