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C语言实现字节流与十六进制字符串的相互转换

C语言实现字节流与十六进制字符串的相互转换

作者: 听力巴士 | 来源:发表于2019-06-07 12:15 被阅读0次
    //字节流转换为十六进制字符串  
    void ByteToHexStr(const unsigned char* source, char* dest, int sourceLen)  
    {  
        short i;  
        unsigned char highByte, lowByte;  
      
        for (i = 0; i < sourceLen; i++)  
        {  
            highByte = source[i] >> 4;  
            lowByte = source[i] & 0x0f ;  
      
            highByte += 0x30;  
      
            if (highByte > 0x39)  
                    dest[i * 2] = highByte + 0x07;  
            else  
                    dest[i * 2] = highByte;  
      
            lowByte += 0x30;  
            if (lowByte > 0x39)  
                dest[i * 2 + 1] = lowByte + 0x07;  
            else  
                dest[i * 2 + 1] = lowByte;  
        }  
        return ;  
    }  
      
    //字节流转换为十六进制字符串的另一种实现方式  
    void Hex2Str( const char *sSrc,  char *sDest, int nSrcLen )  
    {  
        int  i;  
        char szTmp[3];  
      
        for( i = 0; i < nSrcLen; i++ )  
        {  
            sprintf( szTmp, "%02X", (unsigned char) sSrc[i] );  
            memcpy( &sDest[i * 2], szTmp, 2 );  
        }  
        return ;  
    }  
      
    //十六进制字符串转换为字节流  
    void HexStrToByte(const char* source, unsigned char* dest, int sourceLen)  
    {  
        short i;  
        unsigned char highByte, lowByte;  
          
        for (i = 0; i < sourceLen; i += 2)  
        {  
            highByte = toupper(source[i]);  
            lowByte  = toupper(source[i + 1]);  
      
            if (highByte > 0x39)  
                highByte -= 0x37;  
            else  
                highByte -= 0x30;  
      
            if (lowByte > 0x39)  
                lowByte -= 0x37;  
            else  
                lowByte -= 0x30;  
      
            dest[i / 2] = (highByte << 4) | lowByte;  
        }  
        return ;  
    }  
    

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