题目描述
从上到下按层打印二叉树,同一层结点从左至右输出。每一层输出一行。
/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};
*/
class Solution {
public:
vector<vector<int> > Print(TreeNode* pRoot) {
//二叉树层次遍历结果
vector<vector<int>>result;
//二叉树当前层遍历结果
vector<int>layer_result;
//vector 存储当前层的结点。
vector<TreeNode*>current_layer;
//vector 存储下一层的结点。
vector<TreeNode*>next_layer;
current_layer.push_back(pRoot);
if (pRoot == NULL) {
return result;
}
while (!current_layer.empty())
{
layer_result.push_back(current_layer[0]->val);
if (current_layer[0]->left != NULL) {
next_layer.push_back(current_layer[0]->left);
}
if (current_layer[0]->right != NULL) {
next_layer.push_back(current_layer[0]->right);
}
current_layer.erase(current_layer.begin());
if (current_layer.empty()) {
//二叉树下一层结点作为当前层结点
current_layer.assign(next_layer.begin(),next_layer.end());
//清空下一层结点结果
next_layer.clear();
//存储遍历当前层结果
result.push_back(layer_result);
//清空当前层遍历结果。
layer_result.clear();
}
}
return result;
}
};
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