输入两棵二叉树A,B,判断B是不是A的子结构。(ps:我们约定空树不是任意一个树的子结构)
package 剑指Offer.树的子结构;
public class Solution {
public boolean HasSubtree(TreeNode root1, TreeNode root2) {
if (root2 == null) {
return false;
}
if (root1 == null) {
return false;
}
boolean flag = false;
if (root1.val == root2.val) {
flag = isSubtree(root1.left, root2.left) && isSubtree(root1.right, root2.right);
}
if (!flag) {
flag = HasSubtree(root1.left, root2);
if (!flag) {
flag = HasSubtree(root1.right, root2);
}
}
return flag;
}
private boolean isSubtree(TreeNode root1, TreeNode root2) {
if (root2 == null) {
return true;
}
if (root1 == null) {
return false;
}
if (root1.val == root2.val) {
return isSubtree(root1.left, root2.left) && isSubtree(root1.right, root2.right);
}
return false;
}
}
class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
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