python的对象如何转换为json输出

在我的《把python的statsmodels通过json接口api的形式实现》中，通过下面的代码得到一个结果对象。

import statsmodels.api as sm
import json
x1 = [[4,67,662],[9,19,618],[6,49,372],[6,33,58],[1,18,153],[2,78,938],[3,15,627],[8,55,191],[2,47,812],[2,83,946],[2,4,895],[9,37,42],[0,1,595],[7,27,392],[5,22,836],[0,12,513],[2,41,601],[3,68,615],[2,23,649],[1,98,9],[9,40,32],[5,77,798],[1,10,903],[1,53,772],[7,20,716],[2,35,678],[5,52,258],[7,31,814],[2,30,577]]
y1 = [2857.0163,2547.5962,1647.6061,343.8966,668.2108,3990.0414,2559.0662,945.1439,3393.1068,4037.1068,3596.0458,297.5798,2383.6193,1663.8839,3420.5135,2088.0197,2531.2703,2670.7878,2669.8044,332.9981,266.718,3433.975,3644.3636,3249.3518,2938.0325,2821.3308,1198.4373,3363.5752,2402.6042]
x1 = sm.add_constant(x1)
model = sm.OLS(y1, x1)
rs = model.fit()

这个rs对象包含了20多个方法和属性，我们如何方便的把他转换为可以json的格式输出呢？
首先根据rs的属性方法的清单，创建一个类，我这里只用部分属性做展示

class obj_rs:
    HC0_se = list
    aic = float
    bic = float
    bse = list
    def __init__(self, HC0_se,aic,bic,bse,):
        self.HC0_se = HC0_se
        self.aic = aic
        self.bic = bic
        self.bse = bse

#对象初始化
c =obj_rs(
    rs.HC0_se.tolist(),
    rs.aic,
    rs.bic,
    rs.bse.tolist()
     )
#对象序列化
c= c.__dict__
print(json.dumps(c,ensure_ascii=False,indent=4))

最后如果你用flask的话，通过下面的代码输出即可。

    tmp = json.dumps(c,ensure_ascii=False,indent=4)
    return Response(tmp, mimetype='application/json',headers={"Access-Control-Allow-Origin":"http://127.0.0.0:5000","Access-Control-Allow-Methods":"GET","Access-Control-Allow-Headers":"x-requested-with,content-type","Access-Control-Allow-Credentials":"true"})
    

结果如下图，json就可以随便你怎么使用啦。

statsmodels的rs对象的部分属性返回的json