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作者: Quakerfang | 来源:发表于2017-04-01 14:21 被阅读0次
    ##判断手势锁是否有效
    - (BOOL)isInvalidLockScreenPwd
    {
        NSUserDefaults *userDefault = [NSUserDefaults standardUserDefaults];
        NSTimeInterval nowInterval = [[NSDate date] timeIntervalSince1970];
        NSInteger type = [g_configDic[@"vpn_logintype"] intValue];
        BOOL shareLogin = [g_configDic[@"share_login"] boolValue];
        BOOL patternFlag = [g_configDic[@"pattern_lock"] boolValue];
        NSString *vpn = [InjectConfig sharedInstance].realAddr;
        NSString *gesturePwd = [SfCommon passwordForAccount:kLockGesturePswd andShareLogin:shareLogin andVpnAddress:vpn];
        NSString *session = [SfCommon passwordForAccount:vpn andShareLogin:shareLogin andVpnAddress:@""];
        NSString *times = [SfCommon passwordForAccount:KLockErrorTimes andShareLogin:shareLogin andVpnAddress:vpn];
        long ackOutTime = 0;
        long ackResTime = 0;
        if(!shareLogin) {
            //判断是否有手势密码
            if(gesturePwd.length != 0) {
                ackOutTime = [[userDefault objectForKey:KAckOutTime] longLongValue];
                ackResTime = [[userDefault objectForKey:KAckLastResTime] longLongValue];
            }
        } else {
            NSString *outAccount = [NSString stringWithFormat:@"%@%@",vpn,KAckOutTime];
            NSString *resAccount = [NSString stringWithFormat:@"%@%@",vpn,KAckLastResTime];
            if(gesturePwd.length != 0) {
                ackOutTime = [[SSKeychain passwordForService:KServive_Sangfor account:outAccount] intValue];
                ackResTime = [[SSKeychain passwordForService:KServive_Sangfor account:resAccount] intValue];
            }
        }
        if((gesturePwd.length != 0)&&(ackOutTime+ackResTime > nowInterval)&&(type == 2)&&patternFlag&&session&&[times intValue]>0)
        {
            return YES;
        }else {
            info(MODULE_SDK,@"password:%@  acktimeResult:%d  patternFlag:%d  session:%@",gesturePwd,(ackOutTime+ackResTime > nowInterval),patternFlag,session);
        }
        return NO;
    }
    

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