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算法|62\. 不同路径、63\. 不同路径 II

算法|62\. 不同路径、63\. 不同路径 II

作者: 激扬飞雪 | 来源:发表于2022-12-22 23:00 被阅读0次

    一、 62. 不同路径

    题目链接:https://leetcode.cn/problems/unique-paths/

    class Solution {
        public int uniquePaths(int m, int n) {
            int[][] dp = new int[m][n];
            for (int i = 0; i < m; i++) dp[i][0] = 1;
            for (int j = 0; j < n; j++) dp[0][j] = 1;
            for (int i = 1; i < m; i++) {
                for (int j = 1; j < n; j++) {
                    dp[i][j] = dp[i- 1][j] + dp[i][j - 1]; 
                }
            }
            return dp[m - 1][n - 1];
        }
    }
    

    二、 63. 不同路径 II

    题目链接:https://leetcode.cn/problems/unique-paths-ii/

    class Solution {
        public int uniquePathsWithObstacles(int[][] obstacleGrid) {
            int m = obstacleGrid.length;
            int n = obstacleGrid[0].length;
            int[][] dp = new int[m][n];
            if (obstacleGrid[0][0] == 1 || obstacleGrid[m - 1][n - 1] == 1) return 0;
            for (int i = 0; i < m && obstacleGrid[i][0] == 0; i++) {
                dp[i][0] = 1; 
            } 
            for (int j = 0; j < n && obstacleGrid[0][j] == 0; j++) {
                dp[0][j] = 1;
            }
    
            for (int i = 1; i < m; i++) {
                for (int j = 1; j < n; j++) {
                    if (obstacleGrid[i][j] == 1) continue;
                    dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
                }
            }
            return dp[m - 1][n - 1];
        }
    }
    

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