7 int LoopDO(int nCount) {
8 int nSum = 0;
mov dword ptr ss:[ebp-8],0
9 int nIndex = 0;
mov dword ptr ss:[ebp-14],0
10 do {
11 nSum += nIndex;
mov eax,dword ptr ss:[ebp-8]
add eax,dword ptr ss:[ebp-14]
mov dword ptr ss:[ebp-8],eax
12 nIndex++;
mov eax,dword ptr ss:[ebp-14]
add eax,1
mov dword ptr ss:[ebp-14],eax
13 } while (nIndex <= nCount);
mov eax,dword ptr ss:[ebp-14]
cmp eax,dword ptr ss:[ebp+8]
jle if.19171C
14 return nSum;
mov eax,dword ptr ss:[ebp-8] 将返回值放入eax
15 }
16 int LoopWhile(int nCount) {
17 int nSum = 0;
mov dword ptr ss:[ebp-8],0
18 int nIndex = 0;
mov dword ptr ss:[ebp-14],0
19 while (nIndex <= nCount)
mov eax,dword ptr ss:[ebp-14]
cmp eax,dword ptr ss:[ebp+8]
jg if.191818
20 {
21 nSum += nIndex;
mov eax,dword ptr ss:[ebp-8]
add eax,dword ptr ss:[ebp-14]
mov dword ptr ss:[ebp-8],eax
22 nIndex++;
mov eax,dword ptr ss:[ebp-14]
add eax,1
mov dword ptr ss:[ebp-14],eax
23 }
jmp if.1917FC
24 return nSum;
mov eax,dword ptr ss:[ebp-8]
25 }
26 int LoopFor(int nCount) {
27 int nSum = 0;
mov dword ptr ss:[ebp-8],0
28 for (int nIndex = 0; nIndex <= nCount; nIndex++) {
mov dword ptr ss:[ebp-14],0
jmp if.191797
mov eax,dword ptr ss:[ebp-14]
add eax,1
mov dword ptr ss:[ebp-14],eax
mov eax,dword ptr ss:[ebp-14]
cmp eax,dword ptr ss:[ebp+8]
jg if.1917AA
29 nSum += nIndex;
mov eax,dword ptr ss:[ebp-8]
add eax,dword ptr ss:[ebp-14]
mov dword ptr ss:[ebp-8],eax
30 }
jmp if.19178E
31 return nSum;
mov eax,dword ptr ss:[ebp-8]
32 }
34 int main(int argc, char *argv[])
35 {
36 if (argc == 0) {
cmp dword ptr ss:[ebp+8],0 和0比较
jne if.191935 jne: 当零标志 Z=0 则跳转； 否则 零标志 Z=1 则顺序执行下一条指令( jump not equall 不相等跳转)
37 printf("justin %d \r\n", argc);
38 }
39 if (argc > 0) {
cmp dword ptr ss:[ebp+8],0
jle if.19194C 小于等于时跳转
40 printf("justin %d \r\n", argc);
41 }
42 if (argc == 0) {
cmp dword ptr ss:[ebp+8],0
jne if.19195B 不相等时跳转
43 argc = 5;
mov dword ptr ss:[ebp+8],5
44 }
45 else {
jmp if.191962
46 argc = 6;
mov dword ptr ss:[ebp+8],6
47 }
49 int nIndex = 1;
mov dword ptr ss:[ebp-8],1
50 switch (nIndex)
mov eax,dword ptr ss:[ebp-8]
mov dword ptr ss:[ebp-D0],eax
51 {
52 case 1: printf("nIndex == 1"); break;
cmp dword ptr ss:[ebp-D0],1
je if.19197D
jmp if.19198C
push if.197B40
call if.191339
add esp,4
54 default:
55 printf("default");
56 break;
57 }
59 LoopDO(2);
push 2
call if.1910FA
add esp,4
60 LoopWhile(2);
push 2
call if.191127
add esp,4
61 LoopFor(2);
push 2
call if.1911E0
add esp,4
63 return 0;
64 }
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