es5和es6两种方法解决 删除两个数组中id相同的对象

es6

let arr1 = [{id:'1',name:'json'},{id:'2',name:'book'} ]
let arr2 = [{id:'1',name:'json',age:'15'},{id:'2',name:'book',age:'16'},{id:'3',name:'ani',age:'17'}] 

//ES6的方法

let add = arr2.filter(item => !arr1.some(ele=>ele.id===item.id));

比如
//删除
        remove(data){
            this.checkedNodes=this.checkedNodes.filter( item=>{
                return !(data.orgCode===item.orgCode)
            });
        }

es5

/ES5的方法

for (var i=0; i<arr2.length; i++) {  
     for (var j=0; j<arr1.length; j++) {  
           if (arr2[i].id == arr1[j].id) {  
                arr2.splice(i, 1);    
           }  
     }  
}  

//es5删除
//删除
        remove(data){
              for (let i=0; i<this.checkedNodes.length; i++) {
                    if (data.orgCode== this.checkedNodes[i].orgCode) {
                        this.checkedNodes.splice(i, 1);
                    }
              }
        }