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219. Contains Duplicate II

219. Contains Duplicate II

作者: 番茄晓蛋 | 来源:发表于2016-12-18 03:22 被阅读10次

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Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k.

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(E) Contains Duplicate (M) Contains Duplicate III

Explanation:
It iterates over the array using a sliding window. The front of the window is at i, the rear of the window is k steps back. The elements within that window are maintained using a set. While adding new element to the set, if add() returns false, it means the element already exists in the set. At that point, we return true. If the control reaches out of for loop, it means that inner return true never executed, meaning no such duplicate element was found.

Reference - simple-java-solution

    // https://discuss.leetcode.com/topic/15305/simple-java-solution/6
    public boolean containsNearbyDuplicate(int[] nums, int k) {
      Set<Integer> set = new HashSet<Integer>();
      for (int i = 0; i < nums.length; i++) {
          if (i > k) set.remove(nums[i - k - 1]);
          if (!set.add(nums[i])) return true;
      }
      return false;
    }

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