Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST.
Basically, the deletion can be divided into two stages:
Search for a node to remove.
If the node is found, delete the node.
Note:Time complexity should be O(height of tree).
450. Delete Node in a BST Given a root node reference of ...
Description Given a root node reference of a BST and a ke...
Given a root node reference of a BST and a key, delete th...
Given a root node reference of a BST and a key, delete th...
删除 BST 中的指定元素，并维持二叉树的结构不变。 遍历，找到元素后： 如果左子节点不存在，返回右子节点 如果右...
450.Delete Node in a BST Given a root node reference of a...
https://leetcode.com/problems/delete-node-in-a-bst/
Solution 1(recursive): root->val = cur->val;root->right =...
题目描述 给定一个二叉搜索树的根节点 root 和一个值 key，删除二叉搜索树中的 key 对应的节点，并保证二...
本文标题：450. Delete Node in a BST
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