题目要求
反转一个单链表。
示例:
输入: 1->2->3->4->5->NULL
输出: 5->4->3->2->1->NULL
思路一
遍历给定链表，摘下节点放到新链表，新链表从后向前构造
→_→ talk is cheap, show me the code
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def reverseList(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
if not head:
return None
new = None
while head:
p = head
head = head.next
p.next = new
new = p
return new
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