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Chapter 8 .分组函数子查询

Chapter 8 .分组函数子查询

作者: GeekGray | 来源:发表于2018-10-04 16:37 被阅读20次

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Chapter 8 .分组函数子查询

/*

含义:
出现在其他语句中的select语句,称为子查询或内查询
外部的查询语句,称为主查询或外查询

分类:
按子查询出现的位置:

select后面:仅仅支持标量子查询

from后面:支持表子查询

where或having后面:★

  • 标量子查询(单行) √

  • 列子查询 (多行) √

  • 行子查询

exists后面(相关子查询)

  • 表子查询

按结果集的行列数不同

  • 标量子查询(结果集只有一行一列)
  • 列子查询(结果集只有一列多行)
  • 行子查询(结果集有一行多列)
  • 表子查询(结果集一般为多行多列)

*/

一、where或having后面

/*

  • 1、标量子查询(单行子查询)

  • 2、列子查询(多行子查询)

  • 3、行子查询(多列多行)

特点:

  • ①子查询放在小括号内

  • ②子查询一般放在条件的右侧

  • ③标量子查询,一般搭配着单行操作符使用

    < >= <= = <>

列子查询,一般搭配着多行操作符使用

in、any/some、all
  • ④子查询的执行优先于主查询执行,主查询的条件用到了子查询的结果

*/

1.标量子查询★

案例1:谁的工资比 Abel 高?

①查询Abel的工资

SELECT salary
FROM employees
WHERE last_name = 'Abel'

②查询员工的信息,满足 salary>①结果

SELECT *
FROM employees
WHERE salary>(

    SELECT salary
    FROM employees
    WHERE last_name = 'Abel'

);

案例2:返回job_id与141号员工相同,salary比143号员工多的员工 姓名,job_id 和工资

①查询141号员工的job_id

SELECT job_id
FROM employees
WHERE employee_id = 141

②查询143号员工的salary

SELECT salary
FROM employees
WHERE employee_id = 143

③查询员工的姓名,job_id 和工资,要求job_id=①并且salary>②

SELECT last_name,job_id,salary
FROM employees
WHERE job_id = (
    SELECT job_id
    FROM employees
    WHERE employee_id = 141
) AND salary>(
    SELECT salary
    FROM employees
    WHERE employee_id = 143

);

案例3:返回公司工资最少的员工的last_name,job_id和salary

①查询公司的 最低工资

SELECT MIN(salary)
FROM employees

②查询last_name,job_id和salary,要求salary=①

SELECT last_name,job_id,salary
FROM employees
WHERE salary=(
    SELECT MIN(salary)
    FROM employees
);

案例4:查询最低工资大于50号部门最低工资的部门id和其最低工资

①查询50号部门的最低工资

SELECT  MIN(salary)
FROM employees
WHERE department_id = 50

②查询每个部门的最低工资

SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id

③ 在②基础上筛选,满足min(salary)>①

SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
    SELECT  MIN(salary)
    FROM employees
    WHERE department_id = 50


);

非法使用标量子查询

SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
    SELECT  salary
    FROM employees
    WHERE department_id = 250


);

2.列子查询(多行子查询)★

案例1:返回location_id是1400或1700的部门中的所有员工姓名

①查询location_id是1400或1700的部门编号

SELECT DISTINCT department_id
FROM departments
WHERE location_id IN(1400,1700)

②查询员工姓名,要求部门号是①列表中的某一个

SELECT last_name
FROM employees
WHERE department_id  <>ALL(
    SELECT DISTINCT department_id
    FROM departments
    WHERE location_id IN(1400,1700)


);

案例2:返回其它工种中比job_id为‘IT_PROG’工种任一工资低的员工的员工号、姓名、job_id 以及salary

①查询job_id为‘IT_PROG’部门任一工资

SELECT DISTINCT salary
FROM employees
WHERE job_id = 'IT_PROG'

②查询员工号、姓名、job_id 以及salary,salary<(①)的任意一个

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<ANY(
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'

) AND job_id<>'IT_PROG';

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<(
    SELECT MAX(salary)
    FROM employees
    WHERE job_id = 'IT_PROG'

) AND job_id<>'IT_PROG';

案例3:返回其它部门中比job_id为‘IT_PROG’部门所有工资都低的员工 的员工号、姓名、job_id 以及salary

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<ALL(
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'

) AND job_id<>'IT_PROG';

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<(
    SELECT MIN( salary)
    FROM employees
    WHERE job_id = 'IT_PROG'

) AND job_id<>'IT_PROG';

3、行子查询(结果集一行多列或多行多列)

案例:查询员工编号最小并且工资最高的员工信息

SELECT * 
FROM employees
WHERE (employee_id,salary)=(
    SELECT MIN(employee_id),MAX(salary)
    FROM employees
);

①查询最小的员工编号

SELECT MIN(employee_id)
FROM employees

②查询最高工资

SELECT MAX(salary)
FROM employees

③查询员工信息

SELECT *
FROM employees
WHERE employee_id=(
    SELECT MIN(employee_id)
    FROM employees


)AND salary=(
    SELECT MAX(salary)
    FROM employees

);

二、select后面

/*

仅仅支持标量子查询

*/

案例:查询每个部门的员工个数

SELECT d.*,(

    SELECT COUNT(*)
    FROM employees e
    WHERE e.department_id = d.`department_id`
 ) 个数
 FROM departments d;

案例2:查询员工号=102的部门名

SELECT (
    SELECT department_name,e.department_id
    FROM departments d
    INNER JOIN employees e
    ON d.department_id=e.department_id
    WHERE e.employee_id=102
    
) 部门名;

3三、from后面

/*

将子查询结果充当一张表,要求必须起别名

*/

案例:查询每个部门的平均工资的工资等级

①查询每个部门的平均工资

SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id


SELECT * FROM job_grades;

②连接①的结果集和job_grades表,筛选条件平均工资 between lowest_sal and highest_sal

SELECT  ag_dep.*,g.`grade_level`
FROM (
    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id
) ag_dep
INNER JOIN job_grades g
ON ag_dep.ag BETWEEN lowest_sal AND highest_sal;

四、exists后面(相关子查询)

/*

语法:exists(完整的查询语句)

结果:1或0

*/

SELECT EXISTS(SELECT employee_id FROM employees WHERE salary=300000);

案例1:查询有员工的部门名

in

SELECT department_name
FROM departments d
WHERE d.`department_id` IN(
    SELECT department_id
    FROM employees

)

exists

SELECT department_name
FROM departments d
WHERE EXISTS(
    SELECT *
    FROM employees e
    WHERE d.`department_id`=e.`department_id`


);

案例2:查询没有女朋友的男神信息

in

SELECT bo.*
FROM boys bo
WHERE bo.id NOT IN(
    SELECT boyfriend_id
    FROM beauty
)

exists

SELECT bo.*
FROM boys bo
WHERE NOT EXISTS(
    SELECT boyfriend_id
    FROM beauty b
    WHERE bo.`id`=b.`boyfriend_id`

);

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