2018-12-27编写一个C#程序，实现输出1~100中所有不

    static void Main(string[] args)
    {
        Console.WriteLine("1-100之间不能被整除的数据为:");
        int [] a =new int [87];
        int c =1;
        int sum = 0;
        for (int i = 1; i < 101; i++)
        {
            if (i % 7 != 0)
            {
                a[c] = i;
                c++;
            }
        }
            for (int b = 1; b < c; b++)
            {
                Console.Write(a[b] + "\t");
                if (b % 4 == 0)
                {
                    Console.WriteLine("");
                }
        }
        for (int d = 0; d <c ; d++)
        {
            sum = sum + a[d];
        }
        Console.WriteLine("\n" + "数据之和为：{0}", sum);
        Console.ReadKey();
    }