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LeetCode - 237. Delete Node in a

LeetCode - 237. Delete Node in a

作者: Sinexs | 来源:发表于2016-01-15 09:05 被阅读0次

Question

删除单链表中的节点

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

链表的定义

 
  // Definition for singly-linked list.
  public class ListNode {
      int val;  // 节点的值
      ListNode next; // 节点的指针
      ListNode(int x) { val = x; }
  }

Solutions

这里要注意不仅要替换链表的指针,值也要换,一开始就只换了指针忘记换值了。

public class Solution {
    public void deleteNode(ListNode node) {
        node.val = node.next.val;
        node.next = node.next.next;
    }
}

Points

  • 是否对节点为null时进行处理
    不太懂为何node.next = node.next.next;这里不判断下

TO DO

  • 链表的基础概念

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