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Maximum Subarray. Θ(n)

Maximum Subarray. Θ(n)

作者: R0b1n_L33 | 来源:发表于2017-09-19 22:37 被阅读8次
///Maximum Subarray. Θ(n)
func maximumSubarray(_ array: [Int]) -> (Int, Int, Int) {
    var low = -1, high = -1, sum = Int.min
    var currentLow = -1, currentHigh = -1, currentSum = Int.min
    for i in 0..<array.count {
        if currentSum < 0 {
            currentSum = array[i]
            currentLow = i
        } else {
            currentSum += array[i]
        }
        currentHigh = i
        if currentSum > sum {
            sum = currentSum
            high = currentHigh
            low = currentLow
        }
    }
    return (low, high, sum)
}

var s = try Int.randomArray(above: -10, under: 10)
maximumSubarray(s)

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