Array:旋转数组的最小数字
作者:
敲一手烂代码 | 来源:发表于
2016-05-20 15:55 被阅读9次public static int minNumberInRotateArray(int [] array) {
if (array==null||array.length==0) {
return 0;
}
int min = Integer.MAX_VALUE;
int start = 0;
int end = array.length-1;
int mid = (start+end)/2;
while (start<end) {
if (array[start]<array[mid]&&array[mid+1]<array[end]) {
min = array[start]<array[mid+1]?array[start]:array[mid+1];
return min;
}
if (array[start]<array[mid]&&array[mid+1]>=array[end]) {
start = mid+1;
mid = (start+end)/2;
}
if (array[start]>=array[mid]&&array[mid+1]<array[end]) {
end = mid;
mid = (start+end)/2;
}
}
return array[start];
}
本文标题:Array:旋转数组的最小数字
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