美文网首页
Python_7_Codecademy_7_Lists, For

Python_7_Codecademy_7_Lists, For

作者: 张一闻 | 来源:发表于2016-04-17 23:34 被阅读22次

    <a href="http://www.jianshu.com/p/54870e9541fc">总目录</a>


    课程页面:https://www.codecademy.com/
    内容包含课程笔记和自己的扩展折腾

    Lists

    • 例如:list_sample = [1, 2, 3, "ZHANG Yong", "张雍"]
    • 和string一样,可以是的:[]
    • 和string一样,也有index,从0开始。
      print list_sample[4] Output: 张雍
    • 可以替换list里面的items,譬如把sample list里面的3换成"ZY":
      list_sample[2] = "ZY"
    • 增加 item: .append():
      list_sample.append(6) # [1, 2, 3, "ZHANG Yong", "张雍", 6]
    • 和string一样,也有长度len()
    • 和string一样,也能部分获取: list_sample[n:m]
    • 询问index: list.index(item) 譬如询问"张雍"的index:
      print list_sample.index("张雍") Output: 4
    • 插入指定位置: list.insert(index, item)
    list_sample = [1, 2, 3, "ZHANG Yong", "张雍"]
    list_sample.insert(1, 1.5)
    # 就变成了:[1, 1.5, 2, 3, "ZHANG Yong", "张雍"]
    
    • 排序list.sort()
    #sort list_A in alphabetical order
    list_A = ["cool", "astronaut", "zebra", "xenophobia", "recursive"]
    list_A.sort()
    print list_A
    

    Output:
    ['astronaut', 'cool', 'recursive', 'xenophobia', 'zebra']

    • **移除item(s): ** list.remove(item)
    list_A = ["cool", "astronaut", "zebra", "xenophobia", "recursive"]
    list_A.remove("cool")
    print list_A
    

    Output:
    ['astronaut', 'zebra', 'xenophobia', 'recursive']

    For loop

    例0:String Looping
    string也是可以loop的:

    for x in "ZHANG_Yong"
        print x
    

    Output:
    Z
    H
    A
    N
    G
    _
    Y
    o
    n
    g
    Process finished with exit code 0

    例1:打印出列表中都有哪些items:

    list_sample = [1, 2, 3, "ZHANG Yong", "张雍"]
    for x in list_sample:
      print "%s is in this list" % x
    

    Output:
    1 is in this list
    2 is in this list
    3 is in this list
    ZHANG Yong is in this list
    张雍 is in this list

    例2:listA是数字,输出其平方,且按照大小排序:

    listA = [6, 7, 1, 9, 0]
    listB = []
    for x in listA:
      listB.append(x**2)
    listB.sort()
    print listB
    

    Output:
    [0, 1, 36, 49, 81]

    例3:多个lists作为arguments

    list_A = [3, 9, 17, 15, 19]
    list_B = [2, 4, 8, 10, 30, 40, 50, 60, 70, 80, 90]
    for a, b in zip(list_A, list_B):
        print max(a, b)
    
    Console:
    3
    9
    17
    15
    30
    

    Dictionaries

    • 和string&list一样,可以是的:{}
    • key-value pairs / tuples: 然后就能通过比较好记的key拿到对应的value
      {key : value, key2 : value2, ...}
    d = {"birthday_day" : "1st", "birthday_month" : "June"}
    print d["birthday_day"]
    

    Output:
    1st

    • 增加tuples: (和往list里面加items类似)
      dictionary[new_key] = new_value
    d = {"birthday_day" : "1st", "birthday_month" : "June"}
    d["fav_fruit"] = "orange"
    print d
    

    Output:
    {'birthday_month': 'June', 'birthday_day': '1st', 'fav_fruit': 'orange'}

    • value可以是list:
    d = {"birthday_day" : "1st", "birthday_month" : "June"}
    d["fav_fruit"] = ["orange", "avocado", "banana"]
    print d
    

    Output:
    {'birthday_month': 'June', 'birthday_day': '1st', 'fav_fruit': ['orange', 'avocado', 'banana']}

    • **len(d): **多少个tuples
    • 删除tuple: del dictionary[key]
    • 更改value: `dictionary[key] = new_value
    • curly braces 之间可以断行:
    d = {
        'birthday_month': 'June', 
        'birthday_day': '1st', 
        'fav_fruit': ['orange', 'avocado', 'banana']
    }
    
    • grab an item from a list in a dictionary
    # grab my first two fav food
    d = {
        'birthday_month': 'June', 
        'birthday_day': '1st', 
        'fav_fruit': ['orange', 'avocado', 'banana']
    }
    print d["fav_fruit"][:2]
    

    Output:
    ['orange', 'avocado']

    • for loop and dictionary:
    d = {
        'fav_fruit': ['orange', 'avocado', 'banana'],
        'birthday_month': 'June', 
        'birthday_day': '1st', 
    }
    # 注意上面dictionary里面tuples的顺序
    for x in d:
        print x + ":", d[x] 
    

    Output:
    birthday_month: June
    birthday_day: 1st
    fav_fruit: ['orange', 'avocado', 'banana']
    注意这里的顺序

    相关文章

      网友评论

          本文标题:Python_7_Codecademy_7_Lists, For

          本文链接:https://www.haomeiwen.com/subject/wdaolttx.html