首先创建XMLHttpRequest对象,第二步调用open方法,第三步监听对象的onload和onerror事件,或用onreadystatechange,最后调用send方法。
完整版
var request = new XMLHttpRequest();
request.open('GET','/xxx',true);
request.onreadystatechange = ()=>{
if(request.readyState === 4 && request.status === 200){
console.log(request.resopnse)
}
};
request.send();
简易版
var request = new XMLHttpRequest();
request.open('GET','/xxx',true);
request.onload =()=>{console.log('成功了')}//request.onerror =()=>{console.log('失败了')}
request.send();
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