UIViewController 跳转用法

本文代码基于xcode9.2， swift4.0

Navigation跳转流程

适用于有树形层级关系的导航逻辑，类似入栈出栈，最底层是NavigationController，每新打开一页，会将先打开的页压入栈中；每关闭一页，会将该页从栈顶移除，然后显示栈顶页

navigate_jump.jpg

实现代码

FirstViewController.swift 跳转下一页代码：

let appDelegate = UIApplication.shared.delegate as! AppDelegate
let mainStoryboard = appDelegate.mainStoryBoard
let secondVC = (mainStoryboard?.instantiateViewController(withIdentifier: "secondVC"))!
self.navigationController?.pushViewController(secondVC, animated: true)

SecondViewController.swift 和 ThirdViewController,跳转下一页和FirstViewController一样

FourthViewController.swift 跳转上一页代码：

self.navigationController?.popViewController(animated: true)

FourthViewController.swift 跳转至第二页代码：

let controller = (self.navigationController?.viewControllers[1])!
self.navigationController?.popToViewController(controller, animated: true)

FourthViewController.swift 跳转至根页代码：

self.navigationController?.popToRootViewController(animated: true)

用法总结

1. 通过storyboard初始化UIViewController用法

    let mainStoryboard = UIStoryboard(name: "Main", bundle: nil)    //根据name获取对应的storyboard
    let viewController = mainStoryboard.instantiateViewController(withIdentifier: "firstvc")    //根据Storyboard Id获取对应的ViewController
   

2. navigateController跳转用法

    self.navigationController?.popViewController(animated: true)    //跳转上一页
    self.navigationController?.popToViewController(controller, animated: true)      //跳转至指定页
    self.navigationController?.popToRootViewController(animated: true)          //跳转至最底页
   

Present跳转流程

适用于详情、评价等无下级层次的逻辑

实现代码

FirstViewController.swift 打开SimpleViewController页：

self.present(simpleVC, animated: true, completion: nil)

SimpleViewController.swift关闭本页

self.dismiss(animated: true, completion: nil)