数组拼接

可以在此基础上无限次叠加拼接次数。

#include<iostream>

int main( ){
    int n = 9;
    int m = 3;
    int r = 4;
    double array[9] = {3,3,3,3,3,5,6,7,9};
    double a[3] = {3,5,7};
    double b[4] = {0,0,0,1};
    int aa[16] = {0};
    int i, j, k;
    for (i = 0; i < n; i++)
        aa[i] = array[i];
//    std::cout << i << std::endl;
    for (j = 0; j < m; j++,i++)
        aa[i] = a[j];
//    std::cout << i << " " << j << std::endl;
    for (k = 0; k < r; j++,i++,k++ )
        aa[i] = b[k];
//    std::cout << k << std::endl;
    for (i = 0; i<m+n+r; i++)
        std::cout << aa[i] << " ";
//    cv::Mat mean = (cv::Mat_<double>(4, 4) << aa[i]);
//    std::cout << "mean=" << mean << std::endl;
    return 0;
}

另一种方法：

#include<iostream>
#include <stdlib.h>
#include <vector>
using namespace std;
//定义指针函数
int *copy(int array[], int a[], int aa[], int n, int m);
int main(){
    int size = 4;
    int a2[4] = {3,3,3,3};
    int a1[4] = {3,5,7,8};
    int a3[9] = {0};
    int *p;
    p = copy(a1, a2, a3, 4,4);
    cout << p[0] << " " << p[0] << " " << p[1] << " " << p[2] << " " << p[3] <<  " " << p[4] << " " << p[4] << " " << p[6] << " " << p[7] << " " << p[8] << " " << p[9] << " " << p[10] <<endl;

    return 0;

}
int *copy(int array[], int a[], int aa[], int n, int m)
{
    int i, j;
    for (i = 0; i < n; i++)
        aa[i] = array[i];
    for (j = 0; j < m; j++,i++)
        aa[i] = a[j];
    for (i = 0; i<m+n; i++)
        //printf("%d,", aa[i]);

    return aa;
}