public class Solution {
public int[] countBits(int num) {
int n[] = new int[num+1];
int base = 1;
n[0] = 0;
for(int i=1, t=0; i<=num; i++, t++) {
if(i == base) {
t = 0;
base *= 2;
}
n[i] = n[t] + 1;
}
return n;
}
}
LeetCode 338. Counting Bits Description Given a non negat...
338. Counting Bits Given a non negative integer number nu...
题目描述 338. Counting Bits Given a non negative integer numb...
338. 比特位计数[https://leetcode-cn.com/problems/counting-bits...
338. 比特位计数[https://leetcode-cn.com/problems/counting-bits...
0X00 leetcode 做了 4 道 leetcode 338. Counting Bits leetcode...
问题描述 Given a non negative integer number num. For every n...
Given a non negative integer numbernum. For every numbers...
Given a non negative integer number num. For every number...
本文标题：338. Counting Bits
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