美文网首页
Java JPA查询方法书写文档

Java JPA查询方法书写文档

作者: 程序员大春 | 来源:发表于2019-11-25 19:07 被阅读0次

引用自:https://www.jianshu.com/u/9c5cb1ee4c46

Keyword Sample JPQL snippet
And findByLastnameAndFirstname … where x.lastname = ?1 and x.firstname = ?2
Or findByLastnameOrFirstname … where x.lastname = ?1 or x.firstname = ?2
Is,Equals findByFirstnameIs,findByFirstnameEquals … where x.firstname = ?1
Between findByStartDateBetween … where x.startDate between ?1 and ?2
LessThan findByAgeLessThan … where x.age < ?1
LessThanEqual findByAgeLessThanEqual … where x.age ⇐ ?1
GreaterThan findByAgeGreaterThan … where x.age > ?1
GreaterThanEqual findByAgeGreaterThanEqual … where x.age >= ?1
After findByStartDateAfter … where x.startDate > ?1
Before findByStartDateBefore … where x.startDate < ?1
IsNull findByAgeIsNull … where x.age is null
IsNotNull,NotNull findByAge(Is)NotNull … where x.age not null
Like findByFirstnameLike … where x.firstname like ?1
NotLike findByFirstnameNotLike … where x.firstname not like ?1
StartingWith findByFirstnameStartingWith … where x.firstname like ?1 (parameter bound with appended %)
EndingWith findByFirstnameEndingWith … where x.firstname like ?1 (parameter bound with prepended %)
Containing findByFirstnameContaining … where x.firstname like ?1 (parameter bound wrapped in %)
OrderBy findByAgeOrderByLastnameDesc … where x.age = ?1 order by x.lastname desc
Not findByLastnameNot … where x.lastname <> ?1
In findByAgeIn(Collection ages) … where x.age in ?1
NotIn findByAgeNotIn(Collectionage) … where x.age not in ?1
TRUE findByActiveTrue() … where x.active = true
FALSE findByActiveFalse() … where x.active = false
IgnoreCase findByFirstnameIgnoreCase … where UPPER(x.firstame) = UPPER(?1)

实例

    public Page<BugInfoDto> getAll(BugInfoDto bugInfoDto) {
        Assert.notNull(bugInfoDto, "参数不能为空");
        List<Sort.Order> orderList = new ArrayList<>();
        orderList.add(new Sort.Order(Sort.Direction.ASC, "priority"));
        orderList.add(new Sort.Order(Sort.Direction.DESC, "id"));
        Sort sort = Sort.by(orderList);
        Pageable pageable = PageRequest.of(bugInfoDto.getPageNumber(), bugInfoDto.getPageSize(), sort);
        Page<BugInfo> bugInfo = bugInfoRepository.findByTitleContainingAndPriorityAndStatusAndHandler(bugInfoDto.getTitle(), bugInfoDto.getPriority(), bugInfoDto.getStatus(), bugInfoDto.getHandler(), pageable);
        ModelMapper modelMapper = new ModelMapper();
        Page<BugInfoDto> result = modelMapper.map(bugInfo, new TypeToken<List<BugInfoDto>>() {
        }.getType());
        return result;
    }

相关文章

网友评论

      本文标题:Java JPA查询方法书写文档

      本文链接:https://www.haomeiwen.com/subject/xqgjwctx.html