You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix =
[
[1,2,3],
[4,5,6],
[7,8,9]
],
rotate the input matrix in-place such that it becomes:
[
[7,4,1],
[8,5,2],
[9,6,3]
]
Example 2:
Given input matrix =
[
[ 5, 1, 9,11],
[ 2, 4, 8,10],
[13, 3, 6, 7],
[15,14,12,16]
],
rotate the input matrix in-place such that it becomes:
[
[15,13, 2, 5],
[14, 3, 4, 1],
[12, 6, 8, 9],
[16, 7,10,11]
]
Solution:
public void rotate(int[][] matrix) {
if(matrix==null || matrix.length==0) return ;
int n=matrix.length;
for(int i=0;i<n;i++){
for(int j=i;j<n;j++){
int tmp=matrix[i][j];
matrix[i][j]=matrix[j][i];
matrix[j][i]=tmp;
}
}
for(int i=0;i<n/2;i++){
for(int j=0;j<n;j++){
int tmp=matrix[j][i];
matrix[j][i]=matrix[j][n-1-i];
matrix[j][n-1-i]=tmp;
}
}
return;
}
时间复杂度:O(n^2)
空间复杂度:O(1)
规律题,不太好找到。右旋90°等同于矩阵先沿对角线互换再沿左右对换。右旋180°,可以进行两次90°旋转,也可以上下对换再左右对换。以此类推。
题目中假定是n*n矩阵,建议还是做一下输入合法性判断。
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