Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15]
, target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
way1:
/**
- Note: The returned array must be malloced, assume caller calls free().
*/
int* twoSum(int* nums, int numsSize, int target) {
int i=0;
int j=0;
int *a;
a = (int *)malloc(2*sizeof(int));
for(;i<numsSize;i++)
{
for(j=0;j<i;j++)
{
if(nums[i] + nums[j] == target)
{
a[0] = j;
a[1] = i;
return a;
}
}
}
return a;
}
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