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42. Trapping Rain Water

42. Trapping Rain Water

作者: bin_guo | 来源:发表于2018-07-23 08:45 被阅读0次

Leetcode: 42. Trapping Rain Water
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.

The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rainwater (blue section) are being trapped.
Example:

Input: [0,1,0,2,1,0,1,3,2,1,2,1]
Output: 6

Solution:
class Solution {
    public int trap(int[] height) {
        if(height == null || height.length == 0)
            return 0;
        int leftIndex = 0, rightIndex = height.length - 1, leftMax = 0, rightMax = 0, result = 0;
        while(leftIndex < rightIndex) {
            leftMax = Math.max(leftMax, height[leftIndex]);
            rightMax = Math.max(rightMax, height[rightIndex]);
            if(leftMax < rightMax) {
                result += leftMax - height[leftIndex];
                leftIndex++;
            }
            else {
                result += rightMax - height[rightIndex];
                rightIndex--;
            }
        }
        return result;
    }
}

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