Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1
Example 2:
Input: [4,1,2,1,2]
Output: 4
这道题使用异或即可,任何数和自己异或都是0,0和任何数异或都是这个数。
class Solution {
public:
int singleNumber(vector<int>& nums) {
int res = 0;
for(auto it : nums){
res ^= it;
}
return res;
}
};
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