美文网首页
Python socket 同时响应多个请求

Python socket 同时响应多个请求

作者: 自我实验室_村君 | 来源:发表于2019-10-16 15:53 被阅读0次
    1. 创建 socket 对象,监听地址
    2. while True: serversocket.accept() 不断接收请求
    3. conn 其实就是 socket 对象,接受到请求之后,conn.recv(1024) 不断拼接出 request,然后解析 request
    4. conn.send(response), conn.close() 响应请求,关掉
    5. 能同时响应多个请求是因为把 handler 部分新增线程来处理
      • 在 socket.accept() 之后,把 handle_connection() 放到线程处理。
    import socket
    import time
    import threading
    
    EOL1 = b'\n\n'
    EOL2 = b'\n\r\n'
    body = b'fuck the world'
    response_params = [
        b'HTTP/1.0 200 OK',
        b'Date: Sat, 10 jun 2017 01:01:01 GMT',
        b'Content-Type: text/plain; charset=utf-8',
        'Content-Length: {}\r\n'.format(len(body)).encode('utf-8'),
        body
    ]
    
    response = b'\r\n'.join(response_params)
    
    def handle_connection(conn, addr):
        request = b""
        while EOL1 not in request and EOL2 not in request:
            request += conn.recv(1024)
        print(request)
    
        time.sleep(1)
        conn.send(response)
        conn.close()
    
    
    def main():
        serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        serversocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
        serversocket.bind(('127.0.0.1', 8080))
        serversocket.listen(20)
        print('http://127.0.0.1:8080')
    
        try:
            while True:
                conn, addr = serversocket.accept()
                # handle_connection(conn, addr) 单线程
                t = threading.Thread(target=handle_connection,
                                     args=(conn, addr))
                t.start()
        finally:
            serversocket.close()
    
    if __name__ == '__main__':
        main()
    
    // 代码来自: https://www.the5fire.com/thread-socketserver.html
    

    相关文章

      网友评论

          本文标题:Python socket 同时响应多个请求

          本文链接:https://www.haomeiwen.com/subject/yfdumctx.html