Amazon OA

作者: AThornBird | 来源:发表于2019-10-09 04:46 被阅读0次
    1. 2SumUniquePairs
    import java.util.HashMap;
    import java.util.Map;
    
    public class twoSumUnique {
        public static int uniquepairs(int[] nums, int target) {
            if (nums == null || nums.length == 0) {
                return 0;
            }
            
            int res = 0;
            Map<Integer, Boolean> mapForPrev = new HashMap<>();
            for (int i = 0; i < nums.length; i++) {
                int diff = target - nums[i];
                if (mapForPrev.containsKey(diff)) {
                    if (!mapForPrev.get(diff)) {
                        mapForPrev.put(diff, true);
                        res++;
                    }
                    mapForPrev.put(nums[i], true);
                } else {
                    mapForPrev.put(nums[i], false);
                }
            }
            return res;
        }
        
        public static void main(String[] args) {
            int[] nums1 = { 1, 1, 2, 45, 46, 46 };
            int target1 = 47;
            System.out.println(uniquepairs(nums1, target1));
            System.out.println("-------------------------------");
            int[] nums2 = {1, 5, 1, 5};
            int target2 = 6;
            System.out.println(uniquepairs(nums2, target2));
        }
    }
    
    1. SubTree
    public class subtree {    
        public boolean isSubtree(TreeNode s, TreeNode t){
            return isSubtree(s, t, false);
        }
        
        public boolean isSubtree(TreeNode s, TreeNode t, boolean flag) {
            if (s == null || t == null) {
                if (s == null && t == null) {
                    return true;
                } else {
                    return false;
                }      
            }
    
            if (s.val != t.val && flag){
                return false;
            }
            
            if (s.val == t.val) {
                flag = true;
                if (isSubtree(s.left, t.left, true) && isSubtree(s.right, t.right, true)) {
                     return true;
                }
            }        
            return isSubtree(s.left, t, false) || isSubtree(s.right, t, false);        
        }
        
    }
    
    class TreeNode {
         int val;
         TreeNode left;
         TreeNode right;
         TreeNode(int x) { val = x; }
    }
    
    1. Search 2D
    public class search2D {
        public boolean searchMatrix(int[][] matrix, int target) {
            if (matrix == null || matrix.length == 0) {
                return false;
            }
            
            int row = matrix.length, col = matrix[0].length;
            int i = 0, j = col - 1;
            while (i < row && j >= 0) {
                if (matrix[i][j] == target) {
                    return true;
                } else if (matrix[i][j] < target) {
                    i++;
                } else if (matrix[i][j] > target) {
                    j--;
                }
            }
            return false;
        }
    }
    
    1. Spiral Matrix
    public class spiralMatrix {
        public int[][] generateMatrix(int n) {
            int[][] res = new int[n][n];
            if (n <= 0) {
                return res;
            }
            int rowBegin = 0, rowEnd = n - 1;
            int colBegin = 0, colEnd = n - 1;
            int num = 1;
            while (rowBegin <= rowEnd && colBegin <= colEnd) {
                for (int j = colBegin; j <= colEnd; j++) {
                    res[rowBegin][j] = num++;
                }
                rowBegin++;
                
                for (int i = rowBegin; i <= rowEnd; i++) {
                    res[i][colEnd] = num++;
                }
                colEnd--;
                
                for (int k = colEnd; k >= colBegin; k--) {
                    res[rowEnd][k] = num++;
                }
                rowEnd--;
                
                for (int m = rowEnd; m >= rowBegin; m--) {
                    res[m][colBegin] = num++;
                }
                colBegin++;
            }
            return res;
        }
    }
    
    1. Merge 2 sorted Linked List
    //import java.util.LinkedList;
    
    public class mergeTwoLists {
        public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
            if (l1 == null) {
                return l2;
            } else if (l2 == null) {
                return l1;
            }
            ListNode dummy = new ListNode(0);
            ListNode prev = dummy;
            while (l1 != null && l2 != null) {
                if (l1.val <= l2.val) {
                    prev.next = l1;
                    l1 = l1.next;
                } else {
                    prev.next = l2;
                    l2 = l2.next;
                }
                prev = prev.next;
            }
            if (l1 != null) {
                prev.next = l1;
            }
            if (l2 != null) {
                prev.next = l2;
            }
            return dummy.next;
        }
    }
    
    class ListNode {
        int val;
        ListNode next;
        ListNode(int x) { val = x; }
    }
    
    1. Copy Random Pointer
    import java.util.*;
    
    class Node {
        public int val;
        public Node next;
        public Node random;
    
        public Node() {}
    
        public Node(int _val,Node _next,Node _random) {
            val = _val;
            next = _next;
            random = _random;
        }
    };
    
    public class copyRandomPointer {
        public Node copyRandomList(Node head) {
            if (head == null) {
                return null;
            }
            
            Node temp = head;
            while (temp != null) {
                Node next = temp.next;
                temp.next = new Node(temp.val, null, null);
                temp.next.next = next;
                temp = next;
            }
            
            temp = head;
            while (temp != null) {
                if (temp.random != null) {
                    temp.next.random = temp.random.next;
                }
                temp = temp.next.next;
            }
            
            temp = head;
            Node copyHead = head.next;
            Node copy = copyHead;
            while (copy.next != null) {
                temp.next = temp.next.next;
                temp = temp.next;
                copy.next = copy.next.next;
                copy = copy.next;
            }
            
            temp.next = temp.next.next;
            return copyHead;
        }
    }
    
    1. Critical Connections
    1. Favorite Geren

    相关文章

      网友评论

          本文标题:Amazon OA

          本文链接:https://www.haomeiwen.com/subject/yncwpctx.html