package leetcode;
import java.util.Arrays;
public class Test {
public static void main(String[] args) {
String a = "999";
String b = "1";
//将两个字符串分解成数组 分别为arr1和arr2
int[] arr1 = new int[a.length()];
int[] arr2 = new int[b.length()];
for (int i = 0; i < a.length(); i++) {
arr1[i] = Integer.parseInt(a.substring(i, i + 1));
}
for (int i = 0; i < b.length(); i++) {
arr2[i] = Integer.parseInt(b.substring(i, i + 1));
}
System.out.println(Arrays.toString(arr1));
System.out.println(Arrays.toString(arr2));
//用carry记录进位值
int carry = 0;
int sum = 0;
int i = arr1.length - 1;
int j = arr2.length - 1;
int[] store = new int[a.length() + 1];
int count = 0;
//将对应的位相加
while (i >= 0 || j >= 0) {
int num1 = i < 0 ? 0 : arr1[i];
int num2 = j < 0 ? 0 : arr2[j];
sum = carry + num1 + num2;
carry = sum / 10;
store[count++] = sum % 10;
i--;
j--;
}
//保存最后一次进位值
store[count] = carry;
System.out.println(Arrays.toString(store));
//如果最后一次进位值为0则舍去
int f = carry == 0 ? store.length - 2 : store.length - 1;
StringBuffer sb = new StringBuffer();
//将所得结果拼接
for (int a1 = f; a1 >= 0; a1--) {
sb.append(store[a1]);
}
System.out.println(sb);
}
}
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