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104. Maximum Depth of Binary Tre

104. Maximum Depth of Binary Tre

作者: SilentDawn | 来源:发表于2018-06-15 10:14 被阅读0次

    Problem

    Given a binary tree, find its maximum depth.

    The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

    Note: A leaf is a node with no children.

    Example

    Given binary tree [3,9,20,null,null,15,7],

        3
       / \
      9  20
        /  \
       15   7
    

    return its depth = 3.

    Code

    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    static int var = [](){
        std::ios::sync_with_stdio(false);
        cin.tie(NULL);
        return 0;
    }();
    class Solution {
    public:
        int maxDepth(TreeNode* root) {
            if(root==NULL)
                return 0;
            int left_dep = maxDepth(root->left);
            int right_dep = maxDepth(root->right);
            return left_dep>right_dep?left_dep+1:right_dep+1;
        }
    };
    

    Result

    104. Maximum Depth of Binary Tree.png

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