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最小二乘法拟合圆

最小二乘法拟合圆

作者: 北风知我意 | 来源:发表于2019-06-22 21:59 被阅读0次

    /**

    * 最小二乘法拟合圆

    * 拟合出的圆以圆心坐标和半径的形式表示

    * 此代码改编自 newsmth.net 的 jingxing 在 Graphics 版贴出的代码。

    * 版权归 jingxing, 我只是搬运工外加一些简单的修改工作。

    */typedef complex POINT;bool circleLeastFit(const std::vector &points, double ¢er_x, double ¢er_y, double &radius)

    {

        center_x = 0.0f;

        center_y = 0.0f;

        radius = 0.0f;

        if (points.size() < 3)

        {

            return false;

        }

        double sum_x = 0.0f, sum_y = 0.0f;

        double sum_x2 = 0.0f, sum_y2 = 0.0f;

        double sum_x3 = 0.0f, sum_y3 = 0.0f;

        double sum_xy = 0.0f, sum_x1y2 = 0.0f, sum_x2y1 = 0.0f;

        int N = points.size();

        for (int i = 0; i < N; i++)

        {

            double x = points[i].real();

            double y = points[i].imag();

            double x2 = x * x;

            double y2 = y * y;

            sum_x += x;

            sum_y += y;

            sum_x2 += x2;

            sum_y2 += y2;

            sum_x3 += x2 * x;

            sum_y3 += y2 * y;

            sum_xy += x * y;

            sum_x1y2 += x * y2;

            sum_x2y1 += x2 * y;

        }

        double C, D, E, G, H;

        double a, b, c;

        C = N * sum_x2 - sum_x * sum_x;

        D = N * sum_xy - sum_x * sum_y;

        E = N * sum_x3 + N * sum_x1y2 - (sum_x2 + sum_y2) * sum_x;

        G = N * sum_y2 - sum_y * sum_y;

        H = N * sum_x2y1 + N * sum_y3 - (sum_x2 + sum_y2) * sum_y;

        a = (H * D - E * G) / (C * G - D * D);

        b = (H * C - E * D) / (D * D - G * C);

        c = -(a * sum_x + b * sum_y + sum_x2 + sum_y2) / N;

        center_x = a / (-2);

        center_y = b / (-2);

        radius = sqrt(a * a + b * b - 4 * c) / 2;

        return true;

    }

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