CodeWars打卡（03）

Details:

Given two arrays of strings a1 and a2 return a sorted array r in lexicographical order of the strings of a1 which are substrings of strings of a2.

Example 1:

• a1 = ["arp", "live", "strong"]
• a2 = ["lively", "alive", "harp", "sharp", "armstrong"]
• returns ["arp", "live", "strong"]

__Example 2: __

• a1 = ["tarp", "mice", "bull"]
• a2 = ["lively", "alive", "harp", "sharp", "armstrong"]
• returns []

Notes:

Arrays are written in "general" notation. See "Your Test Cases" for examples in your language.

In Shell bash a1 and a2 are strings. The return is a string where words are separated by commas.

Beware: r must be without duplicates.

自己写的代码如下:

def in_array(array1, array2):
    array1 = set(array1)
    num = []
    for r1 in array1:
        for r2 in array2:
            if r2.find(r1)!=-1:
                num.append(r1)
                break
    return sorted(num)

• str.find(num,begin,end)-->>num存在于str中返回index,不存在返回-1,begin和end是搜索的range.

第一名代码:

def in_array(a1, a2):
    return sorted({sub for sub in a1 if any(sub in s for s in a2)})

any和all的使用
any(x)判断x对象是否为空对象，如果都为空、0、false，则返回false，如果不都为空、0、false，则返回true
all(x)如果all(x)参数x对象的所有元素不为0、''、False或者x为空对象，则返回True，否则返回False