类似于二分查找
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
if(nums.empty()) return NULL;
return helper(nums, 0, nums.size() - 1);
}
private:
TreeNode* helper(vector<int> nums, int l ,int r){
if(l > r) return NULL;
int mid = (l + r) / 2;
TreeNode* root = new TreeNode(nums[mid]);
root->left = helper(nums, l, mid - 1);
root->right = helper(nums, mid + 1, r);
return root;
}
};
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