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oracle进阶之connect by笔记

oracle进阶之connect by笔记

作者: 晓码君 | 来源:发表于2019-04-23 09:39 被阅读0次

oracle进阶之connect by笔记

connect by 用于存在父子,祖孙,上下级等层级关系的数据表进行层级查询。

语法格式:
   {CONNECT BY [ NOCYCLE ] condition [AND condition]... [ START WITH condition ]
    | START WITH condition CONNECT BY [ NOCYCLE ] condition [AND condition]...
    }

特殊词讲解

start with: 指定起始节点的条件

connect by: 指定父子行的条件关系

prior: 查询父行的限定符,格式: prior column1 = column2 or column1 = prior column2 and ... ,

nocycle: 若数据表中存在循环行,那么不添加此关键字会报错,添加关键字后,便不会报错,但循环的两行只会显示其中的第一条

循环行: 该行只有一个子行,而且子行又是该行的祖先行

connect_by_iscycle: 前置条件:在使用了nocycle之后才能使用此关键字,用于表示是否是循环行,0表示否,1 表示是

connect_by_isleaf: 是否是叶子节点,0表示否,1 表示是

level: level伪列,表示层级,值越小层级越高,level=1为层级最高节点

自定义数据:

--创建表
create table employee(
       emp_id number(18),
       lead_id number(18),
       emp_name varchar2(200),
       salary number(10,2),
       dept_no varchar2(8)
); 
-- 添加数据
insert into employee values('1',0,'king','1000000.00','001'); insert into employee values('2',1,'jack','50500.00','002'); insert into employee values('3',1,'arise','60000.00','003'); 
insert into employee values('4',2,'scott','30000.00','002');
 insert into employee values('5',2,'tiger','25000.00','002'); 
insert into employee values('6',3,'wudde','23000.00','003'); insert into employee values('7',3,'joker','21000.00','003');
commit;

数据列表展示:
  

image

数据树形展示:

image

(1) 查询以emp_id为0开始的节点的所有直属节点

select emp_id,lead_id,emp_name,prior emp_name as lead_name,salary from employee
     start with  lead_id=0 connect by prior emp_id =  lead_id 

-- 等同于
select emp_id,lead_id,emp_name,prior emp_name as lead_name,salary
     from employee
     start with  emp_id=1
     connect by prior emp_id =  lead_id 
image

(2) 以emp_id为6的所有祖先节点

select emp_id,lead_id,emp_name,salary from employee 
       start with emp_id=6 connect by prior lead_id=emp_id;
image

(3) 查询一个节点的叔叔伯父节点

with t as ( select  employee.*,prior emp_name,level le from employee 
       start with lead_id = 0 connect by lead_id=prior emp_id
       ) select *
       from t left join t tt on tt.emp_id=6
       where t.le = (tt.le-1) and t.emp_id not in (tt.lead_id) 
image

(4) 查询族兄

with t as ( select employee.*,prior emp_name,level le from employee 
           start with lead_id=0 connect by lead_id= prior emp_id
       ) select t.*
       from t  t left join t tt on tt.emp_id=6
       where t.le=tt.le and t.emp_id<>6;</pre>
image

(5) level伪列的使用,格式化层级

select lpad(' ',level*2,' ')||emp_name as name,emp_id,lead_id,salary,level from employee
       start with lead_id=0 connect by prior emp_id=lead_id
image

level数值越低级别越高

(6) connect_by_root 查找根节点

select connect_by_root emp_name,emp_name,lead_id,salary from employee where dept_no='002' start with lead_id=1 connect by  prior emp_id = lead_id;
image

(7) 标注循环行

-- 插入一条数据,与另一条emp_id=7的数据组成循环行
       insert into employee values('3',7,'joker_cycle','21000.00','003'); commit; -- connect_by_iscycle("CYCLE"), connect by nocycle
       select emp_id,emp_name,lead_id,salary,connect_by_iscycle as cycle from employee 
       start with lead_id=0 connect by nocycle prior emp_id = lead_id;
image

(8) connect_by_isleaf 是否是叶子节点

select emp_id,emp_name,lead_id,salary,connect_by_isleaf from employee
       start with lead_id=0 connect by nocycle prior emp_id=lead_id;
image

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