704. 二分查找
作者:
Andysys | 来源:发表于
2020-02-02 11:03 被阅读0次 public int search(int[] nums, int target) {
int left = 0;
int right = nums.length - 1;
int mid;
while (left <= right) {
mid = left + (right - left) / 2;
if (nums[mid] == target) {
return mid;
} else if (nums[mid] < target) {
left = mid + 1;
} else {
right = mid - 1;
}
}
return -1;
}
// 模板
int binarySearch(int[] nums, int target) {
if (nums == null || nums.length == 0)
return -1;
int left = 0, right = nums.length - 1;
while (left <= right) {
// Prevent (left + right) overflow
int mid = left + (right - left) / 2;
if (nums[mid] == target) {
return mid;
} else if (nums[mid] < target) {
left = mid + 1;
} else {
right = mid - 1;
}
}
// End Condition: left > right
return -1;
}
本文标题:704. 二分查找
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