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MutationObserver监听dom节点加载完成

MutationObserver监听dom节点加载完成

作者: 踏雪_739a | 来源:发表于2021-12-09 10:36 被阅读0次
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>
<body>
</body>
<script>
   
    var listeners = [];
    var doc = document;
    var MutationObserver = MutationObserver || WebKitMutationObserver;
    var observer;

    function observerEleReady(selector, fn) {
        // 储存选择器和回调函数
        listeners.push({
            selector: selector,
            fn: fn
        });
        if (!observer) {
            // 监听document变化
            observer = new MutationObserver(check);
            observer.observe(doc.documentElement, {
                childList: true,
                subtree: true
            });
        }
        // 检查该节点是否已经在DOM中
        check();
    }

    function check() {
        // 检查是否匹配已储存的节点
        for (var i = 0; i < listeners.length; i++) {
            var listener = listeners[i];
            // 检查指定节点是否有匹配
            var elements = document.querySelectorAll(listener.selector);
            for (var j = 0; j < elements.length; j++) {
                var element = elements[j];
                // 确保回调函数只会对该元素调用一次
                if (!element.ready) {
                    element.ready = true;
                    // 对该节点调用回调函数
                    listener.fn.call(element, element);
                }
            }
        }
    }

    setTimeout(function(){
        document.body.innerHTML = "<h1>aserfdsthhhh</h1>"
    }, 1000);
    
    observerEleReady("h1", function(){
        console.log("h1加载完成")
    })
</script>
</html>

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