美文网首页
映射、元组、集合

映射、元组、集合

作者: lehuai | 来源:发表于2018-01-03 09:58 被阅读0次

    映射

    scala> val map1 = Map ( "scala" -> 1,"java" ->2,"python" -> 3)
    map1: scala.collection.immutable.Map[String,Int] = Map(scala -> 1, java -> 2, python -> 3)
    scala> val map2 = Map(("scala",1),("java",2),("python",3))
    map2: scala.collection.immutable.Map[String,Int] = Map(scala -> 1, java -> 2, python -> 3)
    scala> map1("scala")
    res18: Int = 1
    scala> import scala.collection.mutable._
    import scala.collection.mutable._
    
    scala> val map1 = Map("scala" -> 1,"java" -> 2,"python" ->3)
    map1: scala.collection.mutable.Map[String,Int] = Map(scala -> 1, java -> 2, python -> 3)
    scala> map1("scala") = 6
    
    scala> map1("scala")
    res20: Int = 6
    
    scala> map1.getOrElse("c#",-1)
    res21: Int = -1
    

    元组

    scala> ("scala",1)
    res22: (String, Int) = (scala,1)
    
    scala> val t = ( "scala",100L,3.14,("spark",1))
    t: (String, Long, Double, (String, Int)) = (scala,100,3.14,(spark,1))
    
    scala> t._1
    res23: String = scala
    
    scala> t._3
    res24: Double = 3.14
    
    scala> t._4
    res25: (String, Int) = (spark,1)
    scala> t._4._1
    res26: String = spark
    
    scala> val t,(a,b,c,d) = ("scala",100L,3.14,("spark",1))
    t: (String, Long, Double, (String, Int)) = (scala,100,3.14,(spark,1))
    a: String = scala
    b: Long = 100
    c: Double = 3.14
    d: (String, Int) = (spark,1)
    
    scala> val arr = Array(("lulu",21),("ningning",25),("xiaoyueyue",29))
    arr: Array[(String, Int)] = Array((lulu,21), (ningning,25), (xiaoyueyue,29))
    
    scala> arr.toMap
    res27: scala.collection.immutable.Map[String,Int] = Map(lulu -> 21, ningning -> 25, xiaoyueyue -> 29)
    scala> val arr1 = Array("lulu","ningning","xiaoyueyue")
    arr1: Array[String] = Array(lulu, ningning, xiaoyueyue)
    
    scala> val arr2 = Array(24,25,26,27)
    arr2: Array[Int] = Array(24, 25, 26, 27)
    
    scala> arr1 zip arr2
    res28: Array[(String, Int)] = Array((lulu,24), (ningning,25), (xiaoyueyue,26))
    
    scala> val arr2 = Array(24,25,26,27)
    arr2: Array[Int] = Array(24, 25, 26, 27)
    
    scala> arr1.zip(arr2)
    res29: Array[(String, Int)] = Array((lulu,24), (ningning,25), (xiaoyueyue,26))
    

    集合

    集合之seq

    scala> val list = List(1,2,3)
    list: List[Int] = List(1, 2, 3)
    
    scala> val list2 = 0 :: list
    list2: List[Int] = List(0, 1, 2, 3)
    
    scala> val list3 = list .::(0)
    list3: List[Int] = List(0, 1, 2, 3)
    
    scala> val list4 = 0 +: list
    list4: List[Int] = List(0, 1, 2, 3)
    
    scala> val list5 = list .+:(0)
    list5: List[Int] = List(0, 1, 2, 3)
    
    scala> val list6 = list :+ 4
    list6: List[Int] = List(1, 2, 3, 4)
    
    scala> val list7 = List(5,6,7)
    list7: List[Int] = List(5, 6, 7)
    
    scala> val list8 = list ++ list7
    list8: List[Int] = List(1, 2, 3, 5, 6, 7)
    scala> val list8 = list ++: list7
    list8: List[Int] = List(1, 2, 3, 5, 6, 7)
    scala> val list9 = list ++: list7
    list9: List[Int] = List(1, 2, 3, 5, 6, 7)
    scala> import scala.collection.mutable.ListBuffer
    import scala.collection.mutable.ListBuffer
    
    scala> val list1 = ListBuffer(1,2,3)
    list1: scala.collection.mutable.ListBuffer[Int] = ListBuffer(1, 2, 3)
    
    scala> list1 += 4
    res0: list1.type = ListBuffer(1, 2, 3, 4)
    
    scala> list1
    res1: scala.collection.mutable.ListBuffer[Int] = ListBuffer(1, 2, 3, 4)
    
    scala> list1.append(5)
    
    scala> val list2 = ListBuffer(6,7,8)
    list2: scala.collection.mutable.ListBuffer[Int] = ListBuffer(6, 7, 8)
    
    scala> list1 ++= list2
    res3: list1.type = ListBuffer(1, 2, 3, 4, 5, 6, 7, 8)
    
    scala> list1 ++ list2
    res4: scala.collection.mutable.ListBuffer[Int] = ListBuffer(1, 2, 3, 4, 5, 6, 7, 8, 6, 7, 8)
    
    scala> list1 :+ 4
    res5: scala.collection.mutable.ListBuffer[Int] = ListBuffer(1, 2, 3, 4, 5, 6, 7, 8, 4)
    

    集合之set

    scala> import scala.collection.immutable.HashSet
    import scala.collection.immutable.HashSet
    
    scala> val set1 = new HashSet[Int]()
    set1: scala.collection.immutable.HashSet[Int] = Set()
    
    scala> val set2 = set1 + 1
    set2: scala.collection.immutable.HashSet[Int] = Set(1)
    
    scala> val set3 = set2 ++ Set(2,3,4)
    set3: scala.collection.immutable.HashSet[Int] = Set(1, 2, 3, 4)
    
    scala> import scala.collection.mutable.HashSet
    import scala.collection.mutable.HashSet
    
    scala> val set1 = new HashSet[Int]()
    set1: scala.collection.mutable.HashSet[Int] = Set()
    
    scala> set1 += 1
    res6: set1.type = Set(1)
    
    scala> set1 += 2
    res7: set1.type = Set(1, 2)
    
    scala> set1.add(3)
    res8: Boolean = true
    
    scala> set1 ++= Set(4,5,6)
    res9: set1.type = Set(1, 5, 2, 6, 3, 4)
    
    scala> set1 ++= Set(5,6,7)
    res10: set1.type = Set(1, 5, 2, 6, 3, 7, 4)
    
    scala> set1 -= 1
    res11: set1.type = Set(5, 2, 6, 3, 7, 4)
    
    scala> set1.remove(2)
    res12: Boolean = true
    

    集合之map

    scala> val map1 = new HashMap[String,Int]()
    <console>:11: error: not found: type HashMap
           val map1 = new HashMap[String,Int]()
                          ^
    
    scala> import scala.collection.mutable._
    import scala.collection.mutable._
    
    scala> val map1 = new HashMap[String,Int]()
    map1: scala.collection.mutable.HashMap[String,Int] = Map()
    
    scala> map1("scala") = 1
    
    scala> map1 += (("java",2))
    res14: map1.type = Map(scala -> 1, java -> 2)
    
    scala> map1 += (("python",3),("c#",4))
    res15: map1.type = Map(scala -> 1, java -> 2, c# -> 4, python -> 3)
    
    scala> map1.put("c++",5)
    res16: Option[Int] = None
    
    scala> map1.put("c++",5)
    res17: Option[Int] = Some(5)
    
    scala> map1
    res18: scala.collection.mutable.HashMap[String,Int] = Map(scala -> 1, c++ -> 5, java -> 2, c# -> 4, python -> 3)
    
    scala> map1 -= "java"
    res19: map1.type = Map(scala -> 1, c++ -> 5, c# -> 4, python -> 3)
    
    scala> map1.remove("c++")
    res20: Option[Int] = Some(5)
    
    scala> map1
    res21: scala.collection.mutable.HashMap[String,Int] = Map(scala -> 1, c# -> 4, python -> 3)
    

    相关文章

      网友评论

          本文标题:映射、元组、集合

          本文链接:https://www.haomeiwen.com/subject/agzcnxtx.html