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python基础之线程

python基础之线程

作者: 尛白兔 | 来源:发表于2017-09-14 22:55 被阅读15次

    简单示例

    import threading
    import time
    
    def worker(num):
        time.sleep(1)
        print(num)
        return
    # target参数是线程执行的函数, args是函数的参数,需要一个元组
    for i in range(10):
        t = threading.Thread(target=worker, args=(i,), name="t.%d" % i)
        t.start()
    

    通过继承Thread类来实现

    import threading
    import time
    
    class MyThread(threading.Thread):
        def __init__(self,num):
            threading.Thread.__init__(self)
            self.num = num
    
        def run(self):    # 启动线程就是调用线程的run方法  
            print("running on number:%s" %self.num)
            time.sleep(2)
    
    
    if __name__ == '__main__':  
        t1 = MyThread(1)
        t2 = MyThread(2)
        t1.start()
        t2.start()
    

    threading.RLock和threading.Lock

    RLock允许在同一线程中被多次acquire。而Lock却不允许这种情况。 如果使用RLock,那么acquire和release必须成对出现,即调用了n次acquire,必须调用n次的release才能真正释放所占用的锁。

    加锁的例子

    import time
    from threading import Thread, Lock
    
    value = 0
    lock = Lock()
    
    def getlock():
        global value
        # 加锁是为了防止在同一时间有多个线程操作数据
      # 使用with会自动加锁和释放锁(acquire和release)
        with lock:
            new_value = value + 1
            time.sleep(1)
            value = new_value
    
    threads= []
    for i in range(100):
        t = Thread(target=getlock)
        t.start()
        threads.append(t)
    
    for t in threads:
        # 主线程等待子线程执行完,程序再退出
        t.join()
    
    print(value)
    

    RLock

    rlock = threading.RLock()
    rlock.acquire()
    rlock.acquire()      # 在同一线程内,程序不会堵塞。
    rlock.release()
    rlock.release()      # 有几个acquire就需要几个release
    print("end.")
    

    线程间通信

    1. threading.Event

    Event定义了一个“Flag”,如果“Flag”的值为False,那么当程序执行wait方法时就会阻塞,如果“Flag”值为True,那么wait方法时便不再阻塞(wait默认为阻塞状态)

    import threading
    
    def do(event):
        print('start')
        # 阻塞线程,等待Event传递事件
        event.wait()
        print('execute')
    
    event_obj = threading.Event()
    for i in range(10):
        t = threading.Thread(target=do, args=(event_obj,))
        t.start()
    
    inp = input('input:')
    if inp == 'true':
        event_obj.set()
    

    再来看一个生产者消费者的例子

    #!/usr/bin/env python3.6
    import threading
    import time
    from random import randint
    
    def product(event, l):
    
        integer = randint(10, 100)
        l.append(integer)             # 往列表中添加内容
        print("product", integer)
        event.set()     # 设置flag为True
        print("set")
        time.sleep(1)
    
    def consumer(event, l):
    
        try:
            integer = l.pop()       # 从列表中取出内容
        except:
            pass
        print("cosumer", integer)
        event.wait()      # 检测event状态,如果为false则阻塞
        print("clear")
    
    threads = []
    l = []
    event = threading.Event()
    p = threading.Thread(target=product, args=(event, l))
    p.start()
    threads.append(p)
    
    c = threading.Thread(target=consumer, args=(event, l))
    c.start()
    threads.append(c)
    
    for t in threads:
        t.join()
    
    
    1. Semaphore
      为了防止不同的线程同时对一个公用的资源操作,需要设置同时访问资源的线程数。信号量同步基于内部计数器,acquire()---> 计数器减1(同时访问资源的线程数), release() ---> 计数器加1, 当计数器为0时,调用acquire(),线程阻塞
    import threading
    import time
    def f1(i,lock):
        name = t.getName()  
        with lock:
            print(name, "acquice")
            time.sleep(1)
        print(name, "release")
    
    
    lock = threading.Semaphore(5)
    for i in range(30):
        t = threading.Thread(target=f1,args=(i,lock,))
        t.start()
    
    print('执行结束')
    
    1. Codition
      Condition被称为条件变量,除了提供与Lock类似的acquire和release方法外,还提供了wait和notify方法。
    import threading
    import time
    def consumer(cond):
        with cond:
            cond.wait()    # 阻塞
            print("consumer")
      
    def producer(cond):
        with cond:
            print("producer")
            cond.notify()    # 通知cond释放
      
    condition = threading.Condition()
    c1 = threading.Thread(name="c1", target=consumer, args=(condition,))
      
    p = threading.Thread(name="p", target=producer, args=(condition,))
      
    c1.start()
    time.sleep(2)
    p.start()
    

    线程池

    在标准库中有一个线程池模块

    >>> from multiprocessing.pool import ThreadPool
    >>> pool = ThreadPool(5)
    >>> result = pool.map(lambda x: x**2, range(10))
    >>> print(result)
    [0, 1, 4, 9, 16, 25, 36, 49, 64, 81]
    
    

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