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6. ZigZag Conversion

6. ZigZag Conversion

作者: chaowwwww | 来源:发表于2018-04-10 18:19 被阅读0次
class Solution:
    def convert(self, s, numRows):
        """
        :type s: str
        :type numRows: int
        :rtype: str
        """
        arr = [[] for x in range(numRows)]
        i = 0
        l = len(s)
        n = numRows
        if n == 1:
            return s
        while i < l:
            for j in range(n - 1):
                if i >= l:
                    break
                arr[j].append(s[i])
                i += 1
            for j in reversed(range(1, n)):
                if i >= l:
                    break
                arr[j].append(s[i])
                i += 1
        strs = [''.join(arr[x]) for x in range(n)]
        return ''.join(strs)

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