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Luogu P2278 Code

Luogu P2278 Code

作者: Macesuted | 来源:发表于2020-01-18 14:57 被阅读0次

P2278

#include <cstdio>
#include <queue>

struct task
{
    int number;
    int need;
    int get;
    int grade;
    inline bool operator < (const task &b) const
    {
        return this->grade<b.grade||(this->grade==b.grade&&this->get>b.get);
    }
};

std::priority_queue<task,std::vector<task>,std::less<task>> wait;

int main()
{
    int num,get,times,grade;
    int time=-1;
    while(scanf("%d%d%d%d",&num,&get,&times,&grade)!=EOF)
    {
        while((!wait.empty())&&time+wait.top().need<=get)
        {
            time+=wait.top().need;
            printf("%d %d\n",wait.top().number,time);
            wait.pop();
        }
        if(!wait.empty())
        {
            task cache=wait.top();
            wait.pop();
            cache.need-=get-time;
            wait.push(cache);
        }
        wait.push({num,times,get,grade});
        time=get;
    }
    while(!wait.empty())
    {
        time+=wait.top().need;
        printf("%d %d\n",wait.top().number,time);
        wait.pop();
    }
    return 0;
}


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