Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
class Solution {
public ListNode deleteDuplicates(ListNode head) {
ListNode fakeHead = new ListNode(0);
ListNode pre = fakeHead;
ListNode cur = head;
fakeHead.next = head;
while(cur != null){
while(cur.next != null && cur.next.val == cur.val){
cur = cur.next;
}
if(pre.next == cur){
pre = pre.next;
}else{
pre.next = cur.next;
}
cur = cur.next;
}
return fakeHead.next;
}
}
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