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225. Implement Stack using Queue

225. Implement Stack using Queue

作者: Ysgc | 来源:发表于2020-11-22 10:47 被阅读0次

Implement a last in first out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal queue (push, top, pop, and empty).

Implement the MyStack class:

  • void push(int x) Pushes element x to the top of the stack.
  • int pop() Removes the element on the top of the stack and returns it.
  • int top() Returns the element on the top of the stack.
  • boolean empty() Returns true if the stack is empty, false otherwise.

Notes:

  • You must use only standard operations of a queue, which means only push to back, peek/pop from front, size, and is empty operations are valid.
  • Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue), as long as you use only a queue's standard operations.

Follow-up: Can you implement the stack such that each operation is amortized O(1) time complexity? In other words, performing n operations will take overall O(n) time even if one of those operations may take longer.

Example 1:

<pre style="box-sizing: border-box; font-family: SFMono-Regular, Consolas, "Liberation Mono", Menlo, Courier, monospace; font-size: 13px; margin-top: 0px; margin-bottom: 1em; overflow: auto; background: var(--dark-bg); border-color: rgb(51, 51, 51); color: var(--font) !important; padding: 10px 15px; line-height: 1.6; border-radius: 3px; white-space: pre-wrap;">Input
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 2, 2, false]

Explanation
MyStack myStack = new MyStack();
myStack.push(1);
myStack.push(2);
myStack.top(); // return 2
myStack.pop(); // return 2
myStack.empty(); // return False
</pre>

Constraints:

  • 1 <= x <= 9
  • At most 100 calls will be made to push, pop, top, and empty.
  • All the calls to pop and top are valid.

class MyStack {
public:
    queue<int> q1;
    
    /** Initialize your data structure here. */
    MyStack() {
        
    }
    
    /** Push element x onto stack. */
    void push(int x) {
        q1.push(x);
    }
    
    /** Removes the element on top of the stack and returns that element. */
    int pop() {
        queue<int> q2;
        while (q1.size() > 1) {
            q2.push(q1.front());
            q1.pop();
        }
        int ans = q1.front();
        q1 = q2;
        return ans;
    }
    
    /** Get the top element. */
    int top() {
        return q1.back();
    }
    
    /** Returns whether the stack is empty. */
    bool empty() {
        return q1.empty();
    }
};

/**
 * Your MyStack object will be instantiated and called as such:
 * MyStack* obj = new MyStack();
 * obj->push(x);
 * int param_2 = obj->pop();
 * int param_3 = obj->top();
 * bool param_4 = obj->empty();
 */

Runtime: 0 ms, faster than 100.00% of C++ online submissions for Implement Stack using Queues.
Memory Usage: 7.3 MB, less than 13.87% of C++ online submissions for Implement Stack using Queues.

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