KEYWORD: Sorted array, three pointers, insert from the back;
原题描述为:
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Thinking:
- No new array to be created;
-Insert from the back of the nums1, where works as a created new array;
-Two pointers to compare the last element of nums1 and nums2 => put at the find index of nums1
-last index of nums1 = m+n-1;
CODE:
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