Description:
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
My code:
/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = function(nums, target) {
var firstIndex, secondIndex, arr = [];
for(firstIndex = 0; firstIndex < nums.length - 1; firstIndex++){
for(secondIndex = firstIndex + 1; secondIndex < nums.length; secondIndex++){
if(target == nums[firstIndex] + nums[secondIndex]) {
arr.push(firstIndex);
arr.push(secondIndex);
return arr;
}
}
}
};
`
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