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CH3-UVA1589

CH3-UVA1589

作者: sixleaves | 来源:发表于2016-11-30 22:56 被阅读67次

    UVA1589

    这题是题模拟题, 模拟题最重要的是考虑清楚细节.我一开始的思路没有错.但是读入数据的时候出错了,调了半天.用C来读取数据或写程序要注意的细节真的很多.如果效率上过得去,尽量使用C++来写.

    //
    // Created by sixleaves on 16/11/24.
    //
    
    #include <cstdio>
    #include <cstring>
    
    int board[11][10] = {0};
    
    #define MAX(x, y) ((x) > (y)? (x) : (y))
    
    bool aviableGPos(int x, int y) {
    
        if (x >= 1 && x <=3 && y >=4 && y <=6) return true;
        if (x >= 8 && x <= 10 && y >=4 && y <=6) return true;
        return false;
    }
    
    bool aviableBoardPos(int x, int y) {
    
        if (x >=1 && x <=10 && y >=1 && y <=9) return true;
        return false;
    }
    
    bool isleg(int hx, int hy, int gx, int gy) {
    
        // 竖直方向
        int d = hx - gx < 0? gx -hx : hx -gx;
        if (d == 2) {
            // 马再将下面
            if (hx > gx) {
    
                if (board[hx - 1][hy] != 0) return true;
                return false;
            }else {
                if (board[hx + 1][hy] !=0) return true;
                return false;
            }
    
        }else { // 水平方向
            d = hy - gy < 0? gy -hy : hy -gy;
            if (2 == d) {
                // 马在将水平方向的右侧
                if (hy > gy) {
                    if (board[hx][hy - 1] != 0) return true;
                    return false;
                } else {
                    if (board[hx][hy + 1] != 0) return true;
                    return false;
                }
            }
            return true;
        }
    
    }
    
    
    // == -1表示该位置不合法. 0表示该位置不会将死, 1表示该位置会被将死
    int checkmate(int x, int y, int lastX, int lastY) {
    
        int ischeckmate = 0;
        char eatPiece ;
        // 将军的位置是合法的
        if (!aviableGPos(x, y)) return -1;
        else {
            // 吃掉棋子或者移动到该位置
            eatPiece = board[x][y];
            board[x][y] = 0;
        }
    
        for (int i = 1; i <= 10; i++) {
    
            for (int j = 1; j <= 9; j++) {
    
                switch (board[i][j]) {
                    // chariot
                    case 'R': {
    
                        if (x == i) {
                            int maxC = MAX(j, y);
                            int minC = j + y - maxC;
                            ischeckmate = 1;
                            for (int k = minC + 1; k < maxC; k++) if (board[i][k] != 0) ischeckmate = 0;
                        }
    
                        if (y == j) {
                            int maxC = MAX(x, i);
                            int minC = i + x - maxC;
                            ischeckmate = 1;
                            for (int k = minC + 1; k < maxC; k++) if (board[k][j] != 0) ischeckmate = 0;
                        }
    
                        // 如果能将死, 则需要悔棋
                        if (ischeckmate == 1) {
    
                            board[x][y] = eatPiece;
                            return 1;
                        }
    
                        break;
                    }
                    case 'H': {
    
                        int dx[] = {2, 2, -2, -2, 1, -1, 1, -1};
                        int dy[] = {1, -1, 1, -1, 2, -2, -2, 2};
    
                        for (int k = 0; k < 8; k++) {
    
    
    
                            int hx = i + dx[k];
                            int hy = j + dy[k];
                            if (hx == x && hy == y) {
                                // check horse leg
                                ischeckmate = 0;
                                if (!isleg(i, j, x, y))
                                    ischeckmate = 1;
                                break;
                            }
    
                        }
    
    
                        if (ischeckmate == 1) {
    
                            board[x][y] = eatPiece;
                            return 1;
                        }
    
                        break;
                    }
                    case 'G': {
    
                        if (y == j) {
                            int maxC = MAX(x, i);
                            int minC = i + x - maxC;
                            ischeckmate = 1;
                            for (int k = minC + 1; k < maxC; k++) if (board[k][j] != 0) ischeckmate = 0;
                        }
    
    
                        if (ischeckmate == 1) {
                            board[x][y] = eatPiece;
                            return 1;
                        }
    
                        break;
                    }
                    case 'C': {
    
                        if (x == i) {
                            int maxC = MAX(j, y);
                            int minC = j + y - maxC;
                            int count = 0;
                            for (int k = minC + 1; k < maxC; k++) if (board[i][k] != 0) count++;
                            if (count == 1) ischeckmate = 1;
                        }
    
                        if (y == j) {
                            int maxC = MAX(x, i);
                            int minC = i + x - maxC;
                            int count = 0;
                            for (int k = minC + 1; k <  maxC; k++) if (board[k][j] != 0) count++;
                            if (count == 1) ischeckmate = 1;
                        }
    
    
                        if (ischeckmate == 1) {
                            board[x][y] = eatPiece;
                            return 1;
                        }
    
                        break;
                    }
                    default:
                        break;
                }
    
            }
        }
    
        board[x][y] = eatPiece;
        return ischeckmate;
    
    }
    
    char readchar() {
        char ch;
        for (;;) {
            ch = getchar();
            if (ch != ' ' && ch != '\r' && ch != '\n') return ch;
        }
    }
    
    int main() {
    
        int n, x,y;
    
        while ((scanf("%d%d%d", &n, &x, &y) == 3) && n && x && y) {
    
            memset(board, 0, sizeof(board));
    
            for (int i = 0; i < n; i++) {
                char ch;
                int chx, chy;
                ch = readchar();
                scanf("%d%d",&chx, &chy);
                board[chx][chy] = ch;
            }
    
            bool ischeckMate = true;
            int dx[] = {1, -1, 0, 0};
            int dy[] = {0, 0, 1, -1};
    
            // 先检查是否是fly
    
            for (int i = 0; i < 4; i++) {
                // 试走, 如果不是死期, 则证明这步是可以走的.那么不是死局
                int flag = checkmate(x + dx[i], y +dy[i], x, y);
                if (0 == flag) ischeckMate = false;
            }
    
            if (ischeckMate) printf("YES\n");
            else printf("NO\n");
        }
        return 0;
    }
    
    

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