测试表格
--1.学生表
Student(S,Sname,Sage,Ssex)
--S 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别
--2.课程表
Course(C,Cname,T)
--C --课程编号,Cname 课程名称,T 教师编号
--3.教师表
Teacher(T,Tname)
--T 教师编号,Tname 教师姓名
--4.成绩表
SC(S,C,score)
--S 学生编号,C 课程编号,score 分数
数据库信息
学生表 Student
create table Student(S varchar(10),Sname nvarchar(10),Sage datetime,Ssex nvarchar(10));
insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
insert into Student values('02' , '钱电' , '1990-12-21' , '男');
insert into Student values('03' , '孙风' , '1990-05-20' , '男');
insert into Student values('04' , '李云' , '1990-08-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
insert into Student values('08' , '王菊' , '1990-01-20' , '女');
科目表 Course
create table Course(C varchar(10),Cname nvarchar(10),T varchar(10));
insert into Course values('01' , '语文' , '02');
insert into Course values('02' , '数学' , '01');
insert into Course values('03' , '英语' , '03');
教师表 Teacher
create table Teacher(T varchar(10),Tname nvarchar(10));
insert into Teacher values('01' , '张三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五');
成绩表 SC
create table SC(S varchar(10),C varchar(10),score decimal(18,1));
insert into SC values('01' , '01' , 80);
insert into SC values('01' , '02' , 90);
insert into SC values('01' , '03' , 99);
insert into SC values('02' , '01' , 70);
insert into SC values('02' , '02' , 60);
insert into SC values('02' , '03' , 80);
insert into SC values('03' , '01' , 80);
insert into SC values('03' , '02' , 80);
insert into SC values('03' , '03' , 80);
insert into SC values('04' , '01' , 50);
insert into SC values('04' , '02' , 30);
insert into SC values('04' , '03' , 20);
insert into SC values('05' , '01' , 76);
insert into SC values('05' , '02' , 87);
insert into SC values('06' , '01' , 31);
insert into SC values('06' , '03' , 34);
insert into SC values('07' , '02' , 89);
insert into SC values('07' , '03' , 98);
1.查询"01 "课程比" 02 "课程成绩高的学生的信息及课程分数
select * from (selectstudent.*,c,score from student,sc where student.s=sc.s and c='01')c,(selectstudent.*,c,score from student,sc where student.s=sc.s and c='02')d wherec.s=d.s and c.score >d.score;
1.1查询同时存在"01 "课程和" 02 "课程的情况
1.2查询存在"01 "课程但可能不存在" 02 "课程的情况(不存在时显示为null )
Select * from (select * fromsc where sc.c='01')A left join (select * from sc where sc.c='02')B on A.s=B.swhere B.c is null;
1.3查询不存在"01 "课程但存在" 02 "课程的情况
Select * from (select * fromsc where sc.c='01')A right join (select * from sc where sc.c='02')B on A.s=B.swhere A.c is null;
2.查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
selectst.s,st.sname,avg(score) from student as st,sc where st.s=sc.s group by st.shaving avg(score)>=60;
3.查询在SC表存在成绩的学生信息
Select * from student asst,sc where st.s=sc.s;
4.查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为null )
Select A.s,sname,count(c)选课总数,score 总成绩 from student A left join sc B on A.s=B.s group by A.s;
4.1查有成绩的学生信息
Select A.s,sname,count(c)选课总数,score 总成绩 from student A inner join sc B on A.s=B.s group by A.s ;
5.查询「李」姓老师的数量
Select count(Tname) fromTeacher where Tname like '李%' group by Tname;
6.查询学过「张三」老师授课的同学的信息
Select student.* from studentwhere s in (select s from sc where c in (select c from course where t in(select t from teacher where tname ='张三')));
7.查询没有学全所有课程的同学的信息
Select * from student asst,sc where st.s=sc.s group by st.s having count(st.sname)< 3;
8.查询至少有一门课与学号为"01 "的同学所学相同的同学的信息
Select * from (Select st.*from student as st,sc where st.s=sc.s and sc.c= any (select c from sc where s='01'))A group by s;
9.查询和"01 "号的同学学习的课程完全相同的其他同学的信息
Select st.* from student as
st,sc where st.s=sc.s group by st.s having st.s<>'01' and sum(c)=(select sum(c) from sc where s='01' group by s);
10.查询没学过"张三"老师讲授的任一门课程的学生姓名
Select st.* from student asst,sc where st.s=sc.s and sc.c in (select c from course where t = any (select tfrom teacher where tname='张三'));
11.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
select A.* from student A ,(select * from sc where score <60 group by s having count(s)>=2)B whereA.s = B.s;
or
select A.* from student Ainner join (select * from sc where score <60 group by s havingcount(s)>=2)B on A.s = B.s;
12.检索"01 "课程分数小于60,按分数降序排列的学生信息
Select st.* from student asst,(select * from sc where c='01' and score<60)A where st.s=A.s order byscore desc;
13.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
Select sc.*,平均值from sc left join (select *,avg(score) as平均值from scgroup by s)A on sc.s=A.s order by平均值 desc;
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